Y = - 2x + 8 and Y axis intersection P, translation line y = 3x, through the point P to find the expression

Y = - 2x + 8 and Y axis intersection P, translation line y = 3x, through the point P to find the expression

X = 0 on y-axis
y=-2x+8
If x = 0, then y = 8
So p (0,8)
Y = 3x translation
In translation, the coefficient of X remains unchanged
So it's y = 3x + B
Over P
So 8 = 0 + B
b=8
So it's y = 3x + 8

The line y = - 2x + 8 intersects with the X axis at point P, and the translation line y = 3x passes through point P. the expression of the line after translation is obtained

X = 4, y = 0 (4,0) the slope of translational straight line remains unchanged, y = 3x + B
When (4,0) is brought in, y = 3x-12

If y = 2x + 8 intersects with X axis P, translate the straight line y = 3x so that it passes through point P, find the relation after translation

y=0
2x+8=0
x=-4
So p (- 1,0)
The coefficients of X are equal in translation
So it's y = 3x + B
Over P
0=-3+b
b=3
So it's y = 3x + 3

It is known that the line y = − 23x + 3 intersects the x-axis at point a, intersects the y-axis at point B, and the line y = 2x + B passes through point B and intersects the x-axis at point C. the area of △ ABC is calculated

∵ when y = 0, x = 92; when x = 0, y = 3, ∵ a (92, 0), B (0, 3), ∵ line y = 2x + B passes through point B, ∵ B = 3, ∵ line y = 2x + B. the analytic formula of y = 2X + 3, ∵ C (- 32, 0), ∵ AC = 92 + 32 = 6, ∵ s △ ABC = 12 × 6 × 3 = 9

If the abscissa X of the intersection of the line y = 3x + 6 and the X axis is the solution of the equation 2x + a = 0, then the value of a is______ ．

In the line y = 3x + 6, let y = 0, the solution is x = - 2; that is, the abscissa of the intersection of the line y = 3x + 6 and the X axis is x = - 2; substituting x = - 2 into the equation 2x + a = 0, the solution is: - 4 + a = 0, and the solution is a = 4

The line y = 1 / 2x + 5 / 2 intersects the x-axis and y-axis at points c and D respectively, and the line y = 3x-5 intersects the x-axis and y-axis at points B and D respectively

Reference: it is known that the line y = 1 / 2x + 5 / 2 and y = - x + 1 intersect the x-axis at two points a and B respectively, and the two lines intersect point P. calculate (1) the coordinates of point p; (2) the area of △ PAB
The line y = 1 / 2x + 5 / 2 intersects the x-axis at point a (5,0)
The line y = - x + 1 intersects the X axis at point B (1,0)
Intersection of two straight lines and P (- 1,2)
AB=4
The distance from point P to AB is d = 2
S=1/2*AB*d=4

If the line y = 2x + B intersects with the line y = 3x + 5 at a point on the Y axis, then B =————

B=-10
Let y = 0, x = B / 2 and x = (B-5) / 3, the two equations are equal, and the solution is b = - 10

If a line y = - 2x B and a line y = 3x-5-b intersect at the same point on the X axis, then B=

B / 2 = 5 + B / 3, B = 10 is the same as the coordinate of the intersection of the horizontal axis. If the first formula is + B

If y = 3x-5 and y = - 2x + m intersect at the same point, then M =?

According to the meaning of the title, they intersect on the y-axis, so x = 0. Substituting y = 3x-5, the intersection is (0, - 5)
By substituting this intersection into y = - 2x + m, M = - 5

It is known that the line y = KX + B is parallel to the line y = 2x-1, and the line y = KX + B passes through the point (- 2,5)
(1) Finding the expression of linear function y = KX + B
(2) Judge whether the point C (- 16,9) is on the image of a linear function

From parallel, k = 2
So the line is y = 2x + B
Substituting (- 2,5) into
Find out B
Substitute - 16 to see if y is 9