Let's relax and do a number game: Step 1: take a natural number N1 = 5, calculate N12 + 1 to get A1; step 2: calculate the numbers of A1 Let's relax and play a number game Step 1: take a natural number N1 = 5, and calculate N12 + 1 to get A1; Step 2: calculate the sum of the numbers of A1 to get N2, and calculate N22 + 1 to get A2; Step 3: calculate the sum of the numbers of A2 to get N3, and calculate N32 + 1 to get A3; ………… And so on, the value of A2008?

If you want to know the value of A2008, you must first know n2008, and the value of n2008 is equal to the value of N1 (as for why you can calculate the first six values), so the value of n2008 = N1; thus A2008 = (n2008 ^ 2) + 1 = N1 ^ 2 + 1 = 5 ^ 2 + 1 = 26

The square of X (2x-5) + 4 (5-2x)

x²(2x-5)+4(5-2x)
=x²(2x-5)-4(2x-5)
=(2x-5)(x²-4)
=(2x-5)(x+2)(x-2)

We know that 2A = 3, 2b = 6, 2C = 12, and prove that 2B = a + C

∵2a=3，2b=6，2c=12，∴2a•2c=2a+c=3×12=36，22b=（2b）2=36，∴2a+c=22b，∴2b=a+c．

When a = - 1, B = 1 / 2, C = 0.3, find the quadratic power of formula 2A - (B + C)

Just insert it
=-2-（0.5+0.3)^2
=-2-0.64
=-2.64
I hope I can help you,

The density of alcohol is 0.8 × 103kg / m3. The density of anhydrous alcohol produced by a factory is 0.9g/cm3, which does not meet the production requirements. How much water is contained in 90g anhydrous alcohol produced by the factory?

The volume of anhydrous alcohol is v Wu = m Wu, ρ Wu = 90g0.9g/cm3 = 100cm3; according to the meaning of the title, m liquor + m water = m Wu, V liquor + V water = V Wu; that is: ρ liquor, V liquor + ρ water, V water = m Wu, V liquor + V water = V Wu; substituting the value to get: 0.8g/cm3 × V liquor + 1g / cm3 × V water = 0g, V liquor + V water = 100cm3 to get: V water = 50cm3; the quality of water is: m water = ρ water, V water = 1g / cm3 × 50cm3 = 50g; answer: the anhydrous alcohol contains 50g water

Put the same volume of copper and iron into water and alcohol respectively, who will get more buoyancy?
Please explain

The volume of copper block is the same, so the volume of liquid is the same. It depends on which heavy liquid has higher density and water, so the buoyancy of copper is greater. Another possibility is that the buoyancy of copper is the same. In this case, all of them sink to the bottom, and there is no liquid under the block, so they are not affected by buoyancy

A metal block with a volume of 0.0003 cubic meters is immersed in water to calculate buoyancy

Laoa principle
F float = g discharge = ρ liquid · g · V discharge
0.0003*9.8*1*10^3=

An object has a volume of 100 cubic centimeters. Immerse it in water. What's the buoyancy of an object immersed in alcohol

Since it is submerged, the volume of the row is 100 cubic centimeters, buoyancy in water = 0.0001 * 1000 * 9.8 = 0.98n, similarly in alcohol 0.0001 * 800 * 9.8 = 0.784n

The volume of a piece of iron is 20 cubic centimeters. If it is completely immersed in alcohol, what is its buoyancy?

F floating = g row = ρ alcohol V substance g = 0.8 * 10 ^ 3 * 20 * 10 ^ - 6 * 10 = 0.160n

Compare the buoyancy of 100 cubic centimeter plastic block immersed in water and 125 cubic centimeter copper block immersed in alcohol

Buoyancy = the gravity of the excluded liquid
Immersed in water, the density of water is 1, alcohol is 0.8
We can see that they are the same size