The Nordic line y = KX + B is parallel to the line y = - 2x + 3 and passes through the point (5, - 9). The analytic expression of the line y = KX = B is obtained

The Nordic line y = KX + B is parallel to the line y = - 2x + 3 and passes through the point (5, - 9). The analytic expression of the line y = KX = B is obtained

∵ the line y = KX + B is parallel to the line y = - 2x + 3
∴k=-2,y=-2x+b
Then substituting points (5, - 9) into the above formula, we get b = 1
∴y=-2x+1

It is known that the image of the line y = KX + B passes through point a (0,6) and is parallel to the line y = - 2x
1. If this line passes through point P (m, 2), find the value of M
2. Find the expression of the line where OP is

Solution 1: because the image of the straight line y = KX + B passes through point a (0,6) and is parallel to the straight line y = - 2x, so k = - 2 replaces k = - 2, x = 0, y = 6 with y = KX + B to get - 2 × 0 + B = 6B = 6, so the analytic expression of the straight line is y = - 2x + 6, and then replaces x = m, y = 2 with y = - 2x + 6 to get - 2m + 6 = 2-2m = - 4m = 2. Solution 2: because point O is the origin, the position of point P is

It is known that the line y = KX + B passes through point a (0,6) and is parallel to the line y = - 2x
1. Find the expression of the line
2. If the line passes through the point P (m, 2), find the value of M
3. Find the expression of line OP passing through origin O and point P

Because K is parallel, so K is equal
So y = - 2x + B passes through point (0,6)
The expression is y = - 2x + 6
2. Substituting y = 2 into the expression, the solution is m = x = 2
3. Set of equations
2=2k+b
0=0k+b
Solution
k=1
b=0
So the expression is y = X

It is known that the line y = KX + B passes through point a (0,6) and is parallel to the line y = - 2x
1. Find the expression of the line
If the line passes through point P (m, 2), find the value of M
3. Find the expression of line OP passing through origin O and point P

1. The straight line y = KX + B is parallel to the straight line y = - 2x, so the slopes of the two straight lines are equal, that is, k = - 2. Substitute a (0,6) into 6 = 0 + B = > b = 6. The expression of the straight line: y = - 2x + 62. The straight line passes through the point P (m, 2), so y = - 2x + 6 = > 2 = - 2m + 6 = > m = 23. The straight line passing through the origin O and point P: y = K1X + a substitute (0,0) (2,2) into a =

It is known that the line y = KX + B is parallel to the line y = - 2x and passes through the point a (0,6)
① (2) if the straight line passes through point B (m, 2), find the value of M

① ∵ the line y = KX + B is parallel to the line y = - 2x
∴k=-2
And ∵ the straight line passes through point a (0,6)
Substituting into the solution, B = 6
Therefore, the analytical formula is y = - 2x + 6
② Substituting point B into: 2 = - 2m + 6
So m = 2

It is known that the line y = KX + B passes through point a (0,6) and is parallel to the line y = negative 2x
① Find the function analytic expression of the straight line;
② If this line passes through point P (m, 2), find the value of M

(1) Y = KX + B, passing through point a (0,6), so B = 6 is parallel to the straight line y = - 2x, so k = - 2, so y = - 2x + 6 (2) if this straight line passes through point P (m, 2), when y = 2, m = x = (y-6) / (- 2) = 2, the Dragon whispers for you to solve your doubts, the Phoenix dances for you to ask. Please click [satisfied answer]; if you are not satisfied, please point out that I

Given that the line y = KX + B is parallel to the line y = 2x + 3 and passes through the point (- 3,4), then k =, B =

∵ parallel to the line y = 2x + 3
∴k=2
∵ over point (- 3,4)
∴4=-3k+b
∴b=10
∴k=2,b=10

If the line y = KX + 3 is parallel to the line y = 2x-1, then k =

2

If the line y = KX + B is parallel to the line y = - 2x + 3, then K () B ()

If two lines are parallel, their slopes are the same
That is k = - 2
Intercept can not be the same, the same will become a straight line
That is, B ≠ 3
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When the line y = 2x + B is parallel to the line y = kx-1, K______ ，b______ ．

When ∵ K is equal, the two lines are parallel, ∵ k = 2, and ∵ if B = - 1, the two lines coincide, ∵ B ≠ - 1