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Given a 2 + B 2-10a-6b + 34 = 0, find the value of a + BA − B
∵ A2 + b2-10a-6b + 34 = 0 ∵ a2-10a + 25 + b2-6b + 9 = 0 ∵ (a-5) 2 + (B-3) 2 = 0, the solution is a = 5, B = 3, ∵ a + BA − B = 5 + 35 − 3 = 4
Calculate a ^ 2 + B ^ 2-10a-6b + 34 = 0 to get the value of a and B
a^2+b^2-10a-6b+34=0
(a-5)^2+(b-3)^2+34-25-9=0
(a-5)^2+(b-3)^2=0
a=5,b=3
(16x^4 +1)(4x^2 +1)(2x+1)(1-2x)
(16x^4 +1)(4x^2 +1)(2x+1)(1-2x)
=(16x^4 +1)(4x^2 +1)(1-4x^2)
=(16x^4 +1)(1-16x^4)
=1-256x^8
4x-3y = 4 and 2x-6y = 11 are calculated by addition subtraction elimination method
If equation 2 is multiplied by 2, it becomes 4x-12y = 22, and then subtract equation 2 from equation 1 to get 9y = - 18,
Y = - 2, then bring in formula one to get x = - 1 / 2
Calculation (4x ^ 2 / 2x-1) - 2x-1
2.（x-2y+3)(x+2y-3) 3.m^4-18m^2+81
1.4x²/(2x-1) -2x-1=[4x²-(2x+1)(2x-1)]/(2x-1)=(4x²-4x²+1)/(2x-1)=1/(2x-1)2.(x-2y+3)(x+2y-3)=[x-(2y-3)][x+(2y-3)]=x²-(2y-3)²=x²-4y²+12y-93.m^4 -18m²+81=(m...
2X + (5-x) X4 = 14 2x + 20-4x = 14 why is 4x minus 2x? 4x is preceded by a minus sign, 4x-2x = 20-14 2x = 6 x = 3
The equation is not 2x + (5-x) X4 = 14
2X + 20-4x = 14 move the term on one side, don't you subtract 4x? How did it become 4x minus 2x
4x—2x=20—14
2x=6
x=3
Your arithmetic master is right. The teacher probably hasn't talked about it yet
2X-4X=14-20
Move left and right
20-14=4X-2X
Given that the perimeter of a rectangle is 8a-6b and the length is 2A + B, what is the width of the rectangle?
This is the problem of noodles~
Because the sum of length and width multiplied by 2 is equal to the circumference of the rectangle
（8a-6b）÷2－（2a+b）＝4a-3b-2a-b=2a-4b
(2a ^ b) ^ 2 + (8a ^ 6B ^ 3) / (- 2A ^ 2b) = how much
Given 4A & sup2; + 9b & sup2; - 8A + 6B + 5 = 0, find the value of 2A + 3B
That is, (4a & # 178; - 8A + 4) + (9b & # 178; + 6B + 1) = 0
4(a-1)²+(3b+1)²=0
So A-1 = 3B + 1 = 0
a=1,b=-1/3
So 2A + 3B
=2-1
=1
（2a+b)(2a-b)+8a(-b-2a)
Original formula = 4A ^ 2-B ^ 2-8ab-16a ^ 2
=-12a^2-b^2-8ab
If you want to factorize, go ahead
=-（12a^2+8ab+b^2)
=-(2a+b)(6a+b)
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