How to find the sum function of this power series? ∞ n = 0 ∑ (- 1) ^ (n-1) x ^ 2n / (2n-1) 3 ^ (2n-1)

How to find the sum function of this power series? ∞ n = 0 ∑ (- 1) ^ (n-1) x ^ 2n / (2n-1) 3 ^ (2n-1)


F (x) = the series to be solved = 1 / 3 + the series is summed from n, and an X is proposed in the series,
= 1 / 3 + X sum (n = 1 to infinity) (- 1) ^ (n-1) x ^ (2n-1) / (2n-1) 3 ^ (2n-1) = 1 / 3 + XG (x), and,
Then G '(x) = 3 / (1 + 9x ^ 2), so
g(x)=arctan(3x),f(x)=1/3+xarctan(3x).



The first power of 1.3, plus the second power of 1.3, plus the third power of 1.3,


a1(1-q^n)/(1-q)
q=1.3
a1=1.3
n=100



How to add the negative first power of 3 to the negative second power of 3 to the negative eighth power of 3


Isn't this the sum of the first eight terms of the equal ratio sequence? According to the formula s = 1 / 3 (the eighth power of 1 - (1 / 3)) / (1-1 / 3) =? Let's calculate it by ourselves!



Given a + B-8A + 6B + 25 = 0, find the value of a + ab-6 of a-4ab + 4B


(A-4) + (B + 3) = 0
A=4
B=-3
Party a-4ab + 4B: Party A + ab-6=
(16-12-36)/(16+4*4*3+4*9)=
-32/100=
-0.32



It is known that a, B and C are the three sides of △ ABC and satisfy a & # 178; + B & # 178; - 8a-6b + 25 = 0. The value range of the longest side C in △ ABC is obtained


A-178; + b-178; - 8a-6b + 25 = 0 (a-178; - 8A + 16) + (b-178; - 6B + 9) = 0 (A-4) & 178; + (B-3) & 178; = 0A = 4, B = 3, because C is the longest side, so C ≥ 4, because the sum of two sides is greater than the third side, so C < 7



(8a cubic b-5a cubic B) divided by (4AB)


(8a cubic b-5a cubic B) divided by (4AB)
=2a²-(5/4)a²b²



Square of 0.5a-1 / 4A + cube of 0.125A + cube of 1 / 2a-0.25a-1 / 8A
How to simplify


Square of 0.5a-1 / 4A + cube of 0.125A + cube of 1 / 2a-0.25a-1 / 8A
=Square of 0.5A - cube of 0.5A + 1 / 2A



[a + b] [A-B] + [the third power of 4AB - the square of 8a, the square of B] / 4AB a = 2, B = 1


(a+b)(a-b)+(4ab³-8a²b²)/4ab
=(a²-b²)+[4ab(b²-ab)]/4ab
=a²-b²+b²-ab
=a²-ab
=a(a-b)
=2×(2-1)
=2×1
=2
I understand. Please accept,
If you have any new questions, please ask for help,



(8a cubic - a quadratic B quadratic) / 4AB
calculation
1. (8a cubic - 5A & # 178; B & # 178;) / 4AB
2.(-4x-3y)²
3.(x+2y-3)(x-2y+3)
4.(a+2b-c)²
Factorization
1.a²-2ab+b²-1
2.(m²+n²)²-4m²n²


1. The original formula = 16x-178; + 24xy + 9y \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\(A-B + 1) (a-b



1. A's square-a's cube 2, - 2x cube + 4x 3, xsquare y + 5xy + y 4, - 15nx-20y 5, 8A cube B's square-12ab quartic power + 4AB
1. A's Square - A's cube 2, - 2x's cube + 4x 3, X's Square y + 5xy + y 4, - 15nx-20y 5, 8A's cube B's Square - 12ab's fourth power + 4AB 6, 3x's Square - 6xy + X find the answers to these questions


1. Square of a - cube of a
=a²(1-a)
2. - 2x cube + 4x
=-2x(x²-2)
3. X square y + 5xy + y
=y(x²+5x+1)
4、-15nx-20y
=-5(3nx+4y)
5. 8A cubic B square - 12ab quartic power + 4AB
=4ab(2a²b-3b³+1)
6. 3x square - 6xy + X
=x(3x-6y+1)