The fourth term in the binomial (1 / 2-x) ^ 10 expansion is

The fourth term in the binomial (1 / 2-x) ^ 10 expansion is

(1/2-x)^10
C10 3=10*9*8/3*2*1=120
Item 4 = 120 * (1 / 2) ^ 7 * x ^ 3
=15x^3/16

Find the term with x ^ 5 in the expansion of binomial (x ^ 2-1 / x) ^ 10

The sixth term is the coefficient of x ^ 5, and the value is (10 * 9 * 8 * 7 * 6) / (5 * 4 * 3 * 2 * 1) = 252, so the coefficient of x ^ 5 is - 252. Understand it and hope it can help you!

Binomial reduction (x under 1 + radical) ^ 5 + (x under 1-radical) ^ 5

Let a = 1 + X, B = 1-x, and let a + B = 2, ab = 1-x.a-x.a \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\#178;) (A & #179; + B & #179;) - (AB

In the expansion of [(3rd radical x) - (2 / radical x)] ^ 11, find the binomial coefficient of term x ^ 2

[x^(1/3)-2/x^(1/2)]^11
n/3-(11-n)/2=2 n=9
The term is: C (11,9) x ^ (9 / 3) (- 2) ^ 2 * x ^ (- 2 / 2) = 4C (11,2) x ^ 2 = 220x ^ 2
The binomial coefficient of x ^ 2 is 220