Given A-B = 8, ab = 9, find the value of (a + b) ^ 2

Given A-B = 8, ab = 9, find the value of (a + b) ^ 2


(a+b)^2=a^2+2ab+b^2
(a-b)^2=a^2-2ab+b^2
So (a + b) ^ 2 = (a-b) ^ 2 + 4AB = 8 * 8 + 4 * 9 = 100



AB = 9, a + B = - 3, AA + 3AB + BB


a^2+3ab+b^2 = (a+b)^2+ab=3^2+9=18.



Given a + B = 3, ab = 4, find the value of 3A ^ 2 B + 3AB ^ 2


3a^2b+3ab^2
=3ab(a+b)
=3x4x3
=36