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Given a + B + C = 0, the value of a divided by (2a's Square plus BC) + B divided by (2B's Square plus AC) + C divided by (2C's Square plus AB) is
Given a + B = 5, ab = - 8, find the value of the second power of a-3ab + B
a+b=5
Square on both sides
a²+b²+2ab=25
a²+b²=25-2ab
a²-3ab+b²
=25-2ab-3ab
=25-5ab
=25-5*(-8)
=65
Given a ^ 2 + B ^ 2 = 8, = 9, then the value of AB is
Sorry, I missed a square. Given a ^ 2 + B ^ 2 = 8, ^ 2 = 9, then the value of AB is
a^2+b^2=8
a^2+b^2-2ab+2ab=8
(a-b)^2+2ab=8
Because A-B = 9
9^2+2ab=8
81+2ab=8
2ab=-73
ab=-36.5
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