Find the constant term in the expansion of binomial (x ^ 2-1 / (2 √ x)) ^ 10)

Find the constant term in the expansion of binomial (x ^ 2-1 / (2 √ x)) ^ 10)

(x^2-1/（2√x）)^10
General term
Tr+1=C(10,r)(x²)^(10-r)*[-1/(2√x)]^r
=(-1/2)^rC(10,r)*x^(20-2r)*x^(-r/2)
=(-1/2)^r*C(10,r)x^(20-5r/2)
Let 20-5r / 2 = 0, then r = 8
The constant term in the expansion is
(-1/2)^8*C(10,8)=45/256
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The solution of equation 5x = 14.4 is ()

The solution of equation 5x = 14.4 is (x = 2.88)

There are several sets of integer solutions for the system of Diophantine equations 5x + 10Y = 13

In fact, none of them, because no matter what integers x and Y take, the value of 5x + 10Y cannot have a mantissa of 3