The car is driving on the straight road at the speed of 10m / s, and suddenly found that The car is moving forward on the straight road at the speed of 10m / s, and a bicycle is moving in the same direction at the speed of 2m / s in front of it. The car immediately turns off the accelerator and makes a uniform deceleration movement of a = 4m / S ^ 2. If the car just can't touch the bicycle, what is the size of S

When the car decelerates to the same speed as the bicycle, the distance between them is the closest, because if they don't touch at this time, the distance between them will increase again, and they won't touch each other again
Therefore, the car just does not hit the bicycle, indicating that the speed of the two is equal, and the car just catches up with the bicycle
Time from braking to just catching up: T = (v1-v0) / a = (2-10) / (- 4) = 2S
The distance of car movement: s car = [(10 + 2) / 2] × 2 = 12m
Cycling distance: s bike = 2 × 2 = 4m
S = s car-s bicycle = 8M

When a car starts to move in a straight line with uniform acceleration from a standstill, its speed increases by 10 MGS from the start to the first 100 meters,
The speed of the car increases when it passes the second 100m___ m/s
How to calculate the speed increase after the acceleration? Hope to be clear!

(V end) ^ 2 - (V beginning) ^ 2 = 2aX
The formula above is correct
The acceleration is 0.5
The final velocity is 10 times the root 2

On September 28, 2009, Ningbo Taizhou Wenzhou high-speed railway was officially opened, and Zhejiang railway entered the era of high-speed railway. Assuming that the train is accelerating in a straight line at a certain distance, the displacement is x when the speed increases from 5m / s to 10m / s. then when the speed increases from 10m / s to 15m / s, the displacement is ()
A. 52xB. 53xC. 2xD. 3x

When the train is moving in a straight line with uniform acceleration, 102-52 = 2ax152-102 = 2aX ′, so x ′ = 53x, so B

RELATED INFORMATIONS