When a car passes through a 1100 meter long tunnel at constant speed, its speed is 10m / s when it first enters the tunnel and 12m / s when it leaves the tunnel? (2) What is the average speed through the tunnel?

(1) According to the velocity displacement formula of uniform velocity linear motion: 2As = V2 − V20 solution: a = V2 − v202s = 122 − 1022 × 1100 = 0.02m/s2 (2) average velocity: v = V0 + V2 = 10 + 122 = 11m / s answer: (1) the acceleration of car passing through the tunnel is 0.02m/s2; (2) the average velocity passing through the tunnel is 11m / s

When a 100 meter long train passes through a 1900 meter long tunnel, the speed is 10 m / s when it first enters the tunnel and 12 m / s when it leaves the tunnel. The acceleration of the train passing through the tunnel is calculated

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