On a straight road, a motorcycle starts to catch up with a truck 100 meters in front of it at a constant speed of 10 m / s. if the maximum speed Vmax of the motorcycle is 20 m / s, the motorcycle is required to catch up with the truck within 2 minutes. What conditions should the acceleration of the motorcycle meet?

On a straight road, a motorcycle starts to catch up with a truck 100 meters in front of it at a constant speed of 10 m / s. if the maximum speed Vmax of the motorcycle is 20 m / s, the motorcycle is required to catch up with the truck within 2 minutes. What conditions should the acceleration of the motorcycle meet?

First of all, if we assume that 12at2 = VT + S. substituting t = 120s, v = 10m / s, s = 100m, we can get a = 0.18m/s2, then the speed of motorcycle at the end of 120s is: at = 21.6m/s ＞ 20m / S & nbsp; & nbsp; & nbsp; & nbsp;, which is obviously incorrect

A truck leaves a station at a speed of 10 m / s. after driving for two hours and 15 minutes, a motorcycle chases the truck from the same station at a speed of 54 M / h to find the time and distance to the station

If you are not satisfied with this question, you can answer it as follows: speed = (542 / 36) × 3609 / 36

A car leaves at a speed of 10 m / s 20 m in front of the motorcycle, and the motorcycle chases the car at a speed of 15 m / S 5 s later. The following are the requirements: (1) how long can the motorcycle catch up with the car after it leaves? (2) how far is the place where the motorcycle catches up with the car from the starting point?

（1）.10x+20+5×10＝15x
x=14（s）
（2）15×14-20＝190（m）