If we know the area of a rectangle a ^ 3 + 2A ^ 2 + a (a > 0) and its width is a, then its length is a

If we know the area of a rectangle a ^ 3 + 2A ^ 2 + a (a > 0) and its width is a, then its length is a

Area of rectangle = length × width
So length = (A & # 179; + 2A & # 178; + a) / a = A & # 178; + 2A + 1 = (a + 1) &# 178;
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It is known that the area of a rectangle is 2A2 + AB + 2Ab + B2 (both a and B are positive integers)

∵ 2A2 + AB + 2Ab + B2 = A2 + AB + A2 + 2Ab + B2 = a (a + b) + (a + b) 2 = (a + b) (2a + b), ∵ the length of rectangle is 2A + B, and the width is a + B

There are two small rectangles 5 cm long and a cm wide to form a large rectangle. What is the area of this large rectangle? When a = 4, what is the area of this large rectangle?

(1) The area of this large rectangle is: 5A × 2 = 10A (square centimeter). A: the area of this large rectangle is 10A square centimeter. (2) when a = 4, 10a = 10 × 4 = 40 (square centimeter). A: the area of this large rectangle is 40 square centimeter

Have a rectangle, its length and width ratio is 5:2, diagonal length 29 cm, find the area of this rectangle

(1) The area of the square is: 29 × 29 = 841 (square centimeter), (2) because the ratio of the two right angles is 5:2, the ratio of the shadow part and the middle part in the figure is: (5 × 2 △ 2 × 4): 3 × 3 = 20:9, (3) the area of the shadow part is: 841 × 2020 + 9 = 580 (square centimeter), (4) the original square

The length of a rectangle is 14 cm larger than its width, and 2 / 5 of its length is equal to 3 / 4 of its width

Do you want to use the equation
Binary once is as follows (when you write in braces LZ, remember to add..):
Let the length be xcm and the width be YCM
x=y+14
2/5x=3/4y
The solution is: x = 30
y=16
Therefore, s length = xy = 30 * 16 = 480 (C m2)
One yuan each time:
If the width is xcm, the length is (x + 14) cm
2/5(x+14)=3/4x
The solution is: x = 16
x+14=16+14=30 cm
Therefore, s length = 30 * 16 = 480 C ^

Use 36 cm iron wire to encircle the rectangle. The ratio of length to width is 5:1. How about the area of the rectangle?

Width: 36 ／ 2 ／ (5 + 1) = 3
Length: 3x5 = 15
Area: 3x15 = 45 (cm2)

Use 28 cm long wire to make a rectangle with a length to width ratio of 4:3. What's the area of the rectangle?

Length + width = 28 / 2 = 14
Length = 14x4 / (4 + 3) = 8
Width = 14x3 / (4 + 3) = 6
The area of a rectangle is 8x6 = 48 square centimeters

Use a 30cm iron wire to make a rectangle. It is known that the length of the rectangle is 3cm more than the width. What is the area of the rectangle?

The area is 54 square centimeters, 9 centimeters long and 6 centimeters wide

How much iron wire does it need to make a 10 cm long and 6 cm wide rectangle with iron wire? (ignore the joint) what is the area of this rectangle
Make a square, what is the area of the square; make a circle, what is the area of the circle

The perimeter of rectangle: (10 + 6) × 2 = 32 (CM) area: 10 × 6 = 60 (CM & # 178;) square area: (32 ／ 4) &# 178; = 64 (CM & # 178;) circle area: 3.14 × (32 ／ 3.14 ／ 2) &# 178; = 16 & # 178; △ 3.14 ≈ 81.53 (CM & # 178;) the purpose of the editor is to

Use a 32 cm wire to make a rectangle with a length to width ratio of 3 to 2. What is the area of the rectangle

Let the length and width be x and Y cm respectively
2(x+y)=32
x:y =3:2
x=9.6
y=6.4