Factorization of 4 * x ^ 2 * y ^ 2-6 * x ^ 2 * Y-2 * x * y
Original formula = 2XY (2xy-3x-1)
What is the factorization of (x + 1) (x + 2) x 1 / 4?
It's better to multiply it by four
(4 (x + 1) (x + 2) + 1) / 4
=(4x^2+12x+8+1)/4
=(4x^2+12x+9)/4
=x^2+3x+2.25
=(x+1.5)^2
Factorization: X (x + 1) (x + 2) (x + 3) - 24
Original formula = (X & # 178; + 3x) (X & # 178; + 3x + 2) - 24 let X & # 178; + 3x + 1 = a original formula = (A-1) (a + 1) - 24 = A & # 178; - 1-24 = A & # 178; - 25 = (a-5) (a + 5)
Factorization factor: X (x-1) (x + 1) (x + 2) - 24=______ .
The original formula = x (x + 1) (x-1) (x + 2) - 24 = x (x2-1) (x + 2) - 24 = x (X3 + 2x2-x-2) - 24 = X4 + 2x3-x2-2x-24 = (x4-2x3) + 4x3-x2-2x-24 = X3 (X-2) + 4x3-8x2 + 7x2-2x-24 = (X3 + 4x2) (X-2) + (7x2-14x) + (12x-24) = (X3 + 4x2 + 7x + 12
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