Decompose the following formulas into factors: (1) the square of (a + b) - the square of 4 (a + b) C + 4C

Decompose the following formulas into factors: (1) the square of (a + b) - the square of 4 (a + b) C + 4C

=[(a+b)-2c]²
=(a+b-2c)²

Factorization of a square c-4ac + 4C

=c(a²-4a+4)
=c(a-2)²

Factorization (a + b) ^ 2 + 4 (a + b) C + 4C ^ 2

（a+b）^2+4(a+b)c+4c^2
=(a+b)^2+2*2c*(a+b)+(2c)^2
=(a+b+2c)^2

Factorization: x4-x3 + 3x-3

x4-x3+3x-3
=x³（x-1）+3（x-1）
=（x³+3）（x-1）

The number after represents the power
Factorization p4-7p2 + 1 and X4 + 4x2 + 3x + 4

p4-7p2+1=p^4-7p²+1=p^4+2p²-2p²-7p²+1=p^4+2p²+1-9p²=(p²+1)²-(3p)²=(p²+1+3p)(p²+1-3p) =(p²+3p+1)(p²-3p+1) x4+4x2+3x+4 =x^4+4x²+3x+4=...

Factorization X4 + 3x square y + Y4

Factorization X4 + 3x square y + Y4, can not be decomposed

Factorization: (a-b) ^ 3x (B-A) ^ 4 = ()

(a - b)^3 ·(b - a)^4
= (a - b)^3 · (a - b)^4
= (a - b)^7

Factorization of X4 + x3-4x-16

= x4-16+x3-4x
=（x2-4）（x2+4）+x(x2-4)
=(x2-4)(x2+x+4)
=(x-2)(x+2)(x2+x+4)

Factorization factor X3 + x2 + x-3 x3-6x2 + 11x-6 X4 + x3-7x2-x + 6

(1)x3+x2+x-3=x^3-x+x^2+2x-3 = x(x-1)(x+1)+(x-1)(x+3)= (x-1)(x^2+2x+3)(2)x3-6x2+11x-6 = x^3-x^2 -(5x^2-11x+6) = x^2(x-1)-(5x-6)(x-1)= (x-1)(x^2-5x+6)=(x-1)(x-2)(x-3)(3)x4+x3-7x2-x+6 = x^3(x+1) - (7x-6)...

How to factorize X3 + 6x2 + 7X-2

x3+6x2+7x-2
=x3+2x2+4x2+8x-x-2
=(x+2)(x2+4x-1)
=(x+2)(x2+4x+4-5)
=(x+2)(x+2-√5）(x+2+√5）