Given that the value of polynomial 3x2-4x + 6 is 9, then the value of polynomial x2 − 43x + 6 is () A. 7B. 9C. 12D. 18

Given that the value of polynomial 3x2-4x + 6 is 9, then the value of polynomial x2 − 43x + 6 is () A. 7B. 9C. 12D. 18

The value of ∵ polynomial 3x2-4x + 6 is 9, ∵ 3x2-4x = 3, ∵ x2 − 43x = 1, ∵ x2 − 43x + 6 = 6 + 1 = 7

The known formula 3x2_ The value of 4x + 6 is nine, find x2_ 3 / 4x + 6

∵3x²-4x+6=9
∴3x²-4x=3
∴x²-4/3x=1
That is X & # 178; - 4 / 3x + 6 = 1 + 6 = 7

The following equation (1) 3x2-9 = 0 (2) 3x2-7x + 4 = 0 (3) x2-2 √ 2x + 2 = 0 (4) (x-3) 2 + 4x (x-3) = 0 is solved by an appropriate method

(1)x²=3
x=±√3
(2)(3x-4)(x-1)=0
x=4/3,1
(3)(x-√2)²=0
x=√2
(4)(x-3)(2+4x)=0
(x-3)(x+1/2)=0
x=3,-1/2

The perimeter of a rectangle is 48 decimeters, and the ratio of length to width is 5:3. What is the length and width of the rectangle? What is the area?

The length is: 48 △ 2 × 5 ^ (5 + 3) = 15 decimeters
The width is: 15 × 3 △ 5 = 9 decimeters
The area is: 15 × 9 = 135 square decimeters

The perimeter of a rectangle is 100 cm. If the length increases by one eighth and the width decreases by one ninth, its perimeter remains unchanged. What is the area of the original rectangle

If the title is wrong, the length should be increased by one ninth and the width reduced by one eighth, and its circumference should remain unchanged
Length + width = 50 (CM)
One ninth of the length = one eighth of the width
The ratio of length to width is 9:8,
So length = 450 / 17 (CM), width = 400 / 17 (CM)
Area = 180000 / 289 (cm2)

The perimeter of a rectangle is 100 cm. If the length increases by 1 / 8 and the width decreases by 2 / 9, and its perimeter remains unchanged, what is the area of the original rectangle?

Let the linear equation of two variables be x in length and Y in width, with the following columns: x + y = 100 / 2 and (1 + 8) / 8x + (9-2) / 9 = 100. The solution is x = 32, y = 18 and the area is 576

The circumference of a rectangle is 20 cm. If you increase its length and width by 4 cm, how much is its area increased

20 △ 2 = 10 cm
10 × 4 + 4 × 4 = 56 square centimeter

If the perimeter of a rectangle is 16cm, the lengths of its two sides are xcm and YCM respectively, and 4x-4y-x + 2xy-y-4 = 0, the area of the rectangle can be obtained

Simplify the equation 4 (X-Y) - (X-Y) - 4 = 0 (x-y-2) = 0 to get X-Y = 2. Because x + y = 8, x = 5, y = 3 and the rectangular area is 15

The perimeter of a rectangle is 28cm. If the length of the rectangle is reduced by 2cm and the width is increased by 4cm, a square can be formed. What are the length and width of the original rectangle?

Suppose the length of the rectangle is xcm, then the width is (14-x) cm. According to the meaning of the question, we get: X-2 = (14-x) + 4. The solution is: x = 10, 14-x = 14-10 = 4. Answer: the length of the rectangle is 10cm, and the width is 4cm

The sum of the perimeter of two similar rectangles is 28cm, and the perimeter difference is 8cm?

If the sum of a and B is 28 and the difference is 8, then a and B are 18 and 10 respectively. Because they are similar, the area ratio is the square of the side length ratio, and the perimeter ratio is equal to the side length ratio, so their area ratio is 81:25