Factorization a2-c2 + 4B2 + 4AB

Factorization a2-c2 + 4B2 + 4AB

The result of factoring (a-b) 2-4b2 + 4bc-c2 is?

(a-b)²-4b²+4bc-c²
=(a-b)²-(4b²-4bc+c²)
=(a-b)²-(2b-c)²
=[(a-b)+(2b-c)][(a-b)-(2b-c)]
=(a+b-c)(a-3b+c)
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Factorization of 4a2-4ab-4ac + B2 + C2 + 2BC, please write the process of patient answers, thank you!

4a²-4ab-4ac+b²+c²+2bc
=(4a²-4ab+b²)-(4ac-2bc)+c²
=(2a-b)²-2c(2a-b)+c²
=(2a-b-c)²

If the three sides of a triangle are a, B, C, and A2 + B2 + C2 + 200 = 12a + 16b + 20c, judge the shape of the triangle

a^2+b^2+c^2+200=12a+16b+20c
(a^2-12a+36)+(b^2-16b+64)+(c^2-20c+100)=0
(a-6)^2+(b-8)^2+(c-10)^2=0
a-6=0,b-8=0,c-10=0
∴a=6,b=8,c=10
∵6^2+8^2=10^2
The triangle is a right triangle