Put the proper prime number in the brackets 8 = （ ）＋ （ ﹚ 12 = ﹙ ﹚＋ ﹙ ﹚＋ ﹙ ﹚ 15 = ﹙ ﹚＋﹙ ﹚ 18 = ﹙ ﹚＋﹙ ﹚＋﹙ ﹚ If you think about it, the sum of the maximum factor and the minimum multiple of a number is 62. This number is 62_______

Put the proper prime number in the brackets 8 = （ ）＋ （ ﹚ 12 = ﹙ ﹚＋ ﹙ ﹚＋ ﹙ ﹚ 15 = ﹙ ﹚＋﹙ ﹚ 18 = ﹙ ﹚＋﹙ ﹚＋﹙ ﹚ If you think about it, the sum of the maximum factor and the minimum multiple of a number is 62. This number is 62_______

8 = （3 ）＋ （ 5 ﹚
12 = ﹙2 ﹚＋ ﹙ 3 ﹚＋ ﹙7 ﹚
15 = ﹙2 ﹚＋﹙13 ﹚
18 = ﹙ 2 ﹚＋﹙ 3 ﹚＋﹙13 ﹚
The sum of the maximum factor and the minimum multiple of a number is 62. The number is 31

Fill in the brackets with the appropriate prime number 60 = () + () = () + () + ()

60=（29）+（31）=(13)+(2)+(29)+(29)

Fill in the brackets with the appropriate prime number 44 = () + () = () + ()

44=（13）+（31）=（3）+（41）

Prime, our sum is 8. Prime, our product is 15. What and what

Prime numbers less than 8 have 7, 5, 3
According to the title, it must be 5 and 3
Oh, yes, please

If the reciprocal sum of two prime numbers is equal to 15 / 8, what is the sum of two prime numbers

The title should be "the reciprocal sum of two prime numbers equals 8 / 15"
Expected "reciprocal sum of two prime numbers less than 1"
Let m and n be prime numbers, then
1/m+1/n=（m+n）/(mn)=8/15
The sum of two prime numbers is equal to 8

Which three prime numbers multiply to get 42? 50? 63?

2*3*7=42
2*5*5=50
3*3*7=63

If the three sides a, B and C of △ ABC satisfy the formula A2 + B2 + C2 + 200 = 12a + 16b + 20c, then the area of △ ABC is______ ．

∵ A2 + B2 + C2 + 200 = 12a + 16b + 20c, ∵ a-6) 2 + (B-8) 2 + (C-10) 2 = 0, ∵ a-6) = 0, (B-8) = 0, (C-10) = 0, ∵ a = 6, B = 8, C = 10, ∵ 62 + 82 = 102, ∵ A2 + B2 = C2, ∵ ABC is a right triangle. ∵ s △ ABC = 12 × 6 × 8 = 24

Let F 1 and F 2 be the left and right focus of hyperbola x ^ / A ^ - y ^ / b ^ = 1 respectively, and make a point a on the hyperbola so that the angle f 1af = 60 degrees and / AF1 / = 3 / af2 /

Let | AF1 | = 3q, then | af2 | = Q. from Pythagorean theorem, | F1F2 | = q √ 10 = 2c, that is, C = q √ (10) / 2
The definition of hyperbola is a = (| AF1 | - | af2 |) / 2 = Q
So e = C / a = √ (10) / 2

The two focal points of the hyperbola x2 / 9-y2 / 16 = 1 are F1 and F2. A is a point on the hyperbola if | AF1 | = 7,
Then af2|=
2. If Pf1 ⊥ PF2, then the value of | Pf1 | + | PF2 | is________ ．

（1）
Because the two focuses of the hyperbola x2 / 9-y2 / 16 = 1 are F1 and F2,
And a is a point on the hyperbola, so if | af1-af2 | = 2 × 3 = 6
Because the half focal length is 5 and the half major axis is 3, the distance from the point on the hyperbola to the focus is greater than 2
Because | AF1 | = 7, there are | af2 | = 1 (house) or | af2 | = 13
（2）
Let Pf1 = x, PF2 = y, because P is a point on the hyperbola, so there is
|x-y|=2…… ①
Because Pf1 ⊥ PF2, according to Pythagorean theorem, there are:
x²+y²=8
If (X-Y) ² = 4, then
（x+y）²=16-4=12
So | Pf1 | + | PF2 | = 2 root sign 3

If the two foci F1, F2 and a of the hyperbola are 9 / x square - y square = 1, and | AF1 | = 8, then | af2 | is equal to

From the hyperbolic equation, we can get a square = 9, and from the definition of hyperbola, we can get the global absolute value of af1-af2 = 2A, so af2 = 2 or 14