Given the square of (a + b) + | B + 3 | = B + 3, and | 2a-b-1 | = 0, find the value of a-b

Given the square of (a + b) + | B + 3 | = B + 3, and | 2a-b-1 | = 0, find the value of a-b


∵(a+b)²+|b+3|=b+3
∴ a+b=0, a=-b
∵2a-b-1=0
∴-2b-b-1=0, b=-1/3
a=1/3
a-b=1/3-(-1/3)=2/3



When a = - 1, find 16 + 2A - {8A - [A-9 - (3-6a)]}=


16-2-{-8-[-1-9-(3+6)]}=3



16-8a-【2a-9-(3-6a)】


16-8a-【2a-9-(3-6a)】
=16-8a-【2a-9-3+6a】
=16-8a-【2a+6a-9-3】
=16-8a-(8a-12)
=16-8a-8a+12
=28-16a
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