Square - (n + 1) a + n factorization of a

Square - (n + 1) a + n factorization of a


Square of a - (n + 1) a + n
=a²-na-a+n
=a(a-n)-(a-n)
=(a-1)(a-n)



If we factorize the square of 3x - 6x + 3, the result is


3x^2-6x+3
=3(x^2-2x+1)
=3(x-1)^2



2 [the square of a B + AB] - 2 [the square of AB-1] - the square of 2ab-2ab


2 [the square of a B + AB] - 2 [the square of AB-1] - the square of 2ab-2ab
=2a²b+2ab-2ab²+2-2ab²-2ab
=2a²b-4ab²+2