Given a = 2x square + 3x + 1, B = x square + 2x + 2, when x is what value, A-B = 0?

Given a = 2x square + 3x + 1, B = x square + 2x + 2, when x is what value, A-B = 0?

It is known that a = 2x square + 3x + 1, B = x square + 2x + 2
A-B = 2x square + 3x + 1 - (x square + 2x + 2)
=X²+x-1
=0
x=(-1±√1＋4)/2
=(-1±√5)/2

Square of (x-2x) - 1=

Square difference
The original formula = (X & # 178; - 2x + 1) (X & # 178; - 2x-1)
=(x-1)²(x²-2x-1)

Simplification: the result of the square of (- 2x) · X - (- 2x) is? Urgent!

(-2x)·x-(-2x)²
=-2x²+4x²
=2x²

How to simplify the square of X - 3 + 2x?
Is cross multiplication OK? How to simplify?

Yes
① See X & sup2; + 2x-3
Get (x + 3) (x-1)
② If LZ says X & sup2; - 3 + 2x & sup2
=Extracting common factor from 3x & sup2; - 3
=3 (X & sup2; - 1) according to the square difference
=3（X+1)(X-1)