Given the square of X, y + the square of 2XY = 2, find (the square of X, y-the square of 2XY) + (the square of X, y + the square of 6xy)

Given the square of X, y + the square of 2XY = 2, find (the square of X, y-the square of 2XY) + (the square of X, y + the square of 6xy)

x²y＋2xy²=2
Then:
(x²y－2xy²)＋(x²y＋6xy²)
=2x²y＋4xy²
=2(x²y＋2xy²)
=2×2
=4

Given the square of X, y + the square of 2XY = 2, find the value of (the square of X, y-the square of 2XY) + (the square of X, y + the square of 6xy)

(x's Square, y-2xy's Square) + (x's Square, y + 6xy's Square)
=2 (x squared y + 2XY squared)
=2×2
=4

Let (the square of ax - 2XY + the square of Y) - (- the square of X + 6xy)
(the square of ax minus the square of 2XY + y) minus (the square of negative x plus the square of bxy + 2Y) = the square of 5x minus the square of 9xy + cy, what are the values of a, B, C and C

(the square of ax minus the square of 2XY + y) minus (the square of negative x plus the square of bxy + 2Y) = the square of 5x minus the square of 9xy + cy
ax²-2xy+y²+x²-bxy-2y²=5x²-9xy+cy²
x²(a+1)-xy(2+b)-y²=5x²-9xy+cy²
a+1=5 2+b=9 -1=c
∴a=4
b=7
c=-1