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If f (x + 1) = the square of X + 2x-1, X ∈ [- 1,2], then f (x)=
Let x + 1 = t, then f (x) = xsquare - 2
X belongs to [0,3]
F (x) = x parts (x square + 2x + a)
(1) When a = 1 / 2, X is greater than or equal to 1, find the minimum value of function f (x)
a=1/2
f(x)=x²/x+2x/x+a/x
=x+(1/2)/x+2
X + 1 / (2x) is a check function
So 0 = 1 increments
So x = 1, minimum = f (1) = 7 / 2
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