Ratio size: 1 + 2x ^ 4 and 2x ^ 3 + x ^ 2 Do it by doing the difference How do you make this?

Ratio size: 1 + 2x ^ 4 and 2x ^ 3 + x ^ 2 Do it by doing the difference How do you make this?

The formula of 1 + 2x ^ 4-2x ^ 3 + x ^ 2 will be obtained from the higher order to the lower order
=（x-1）^2*（2x^2+2x+1）≥0

X minus one part X + 1 minus the square of x minus one part x minus 2x times the square of x minus x minus two parts x plus 2x plus 1

Original formula = [(x + 1) / (x-1)] - [(X & # 178; - 2x) / (X & # 178; - 1)] × [(X & # 178; + 2x + 1) / (X & # 178; - X-2)]
=[(x+1)/(x-1)]-{x(x-2)/[(x+1)(x-1)]}×[(x+1)²]/[(x+1)(x-2)]
=[(x+1)/(x-1)]-[x/(x-1)]
=(x+1-x)/(x-1)
=1/(x-1)

The square of (x plus 2) minus the square of (2x minus 1)!
The square velocity of (x plus 2) minus (2x minus 1)

Factorization?
Original formula = (x + 2 + 2x-1) (x + 2-2x + 1)
=(3x+1)(3-x)
Application of square difference formula