Given (x + my) (x + NY) = x2 + 2xy-8y2, find the value of m2N + Mn2

Given (x + my) (x + NY) = x2 + 2xy-8y2, find the value of m2N + Mn2

∵（x+my）（x+ny）=x2+2xy-8y2，∴x2+nxy+mxy+mny2=x2+（m+n）xy+mny2=x2+2xy-8y2，∴m+n=2，mn=-8，∴m2n+mn2=mn（m+n）=-8×2=-16．

Given (x + my) (x + NY) = x2 + 2xy-8y2, find the value of m2N + Mn2

∵（x+my）（x+ny）=x2+2xy-8y2，∴x2+nxy+mxy+mny2=x2+（m+n）xy+mny2=x2+2xy-8y2，∴m+n=2，mn=-8，∴m2n+mn2=mn（m+n）=-8×2=-16．

Given the + 2XY - 8y of (x + my) (x + NY) = x, find the value of (M + n) Mn,

(x+my)(x+ny)
=x^2+(m+n)xy+mny^2
=x^2+2xy-8y^2
The coefficients of corresponding terms are equal
m+n=2,mn=-8
mn(m+n)=-8×2=-16