We know that a = the square of a-2ab = + the square of B, B = the square of a + the square of 2Ab + B. (1) find a + B; (2) find 1 / 4 (B-A)

A=a²-2ab+b²,B=a²+2ab+b²
A+B=(a²-2ab+b²)+(a²+2ab+b²)=2(a²+b²)
B-A=(a²+2ab+b²)+(a²-2ab+b²)=4ab
∴1/4*(B-A)=1/4*4ab=ab

Given a = - 2 of B, find the value of (6ab-7b's Square) of (A's square-2ab)

Given a + B = 2Ab, ab = - 1 / 2, find the square of a (a + b) (a-b) - A (a + b)

A + B = 2Ab, ab = - 1 / 2
∴a+b=-1
ab=-1/2
The square of a (a + b) (a-b) - A (a + b)
=a(a+b)(a-b-a-b)
=-2ab(a+b)
=1

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