xの二乗y+2xyの二乗=2,求(xの二乗y-2xyの二乗)+(xの二乗y+6xyの二乗)

xの二乗y+2xyの二乗=2,求(xの二乗y-2xyの二乗)+(xの二乗y+6xyの二乗)

x²y+2xy²=2
則:
(x²y-2xy²)+(x²y+6xy²))
=2x²y+4xy²
=2(x²y+2xy²)
=2×2
=4