Divide the numbers 4, 6, 8, 21.22, 30 and 35 into two groups so that the product of the four numbers in each group is equal

It is impossible to be equal. The common divisor 11 of 22 appears only once. Obviously, the product of only one of the two groups is a multiple of 11

Divide the eight numbers 6, 4, 8, 30, 21, 35, 33 and 22 into two groups to make the product of the four numbers in each group equal. How to divide them?

Because the first 6, 4 and 8 are single digits, and the last two digits can be split into 5 * 6, 3 * 7, 5 * 7, 3 * 11 and 2 * 11, you just need to observe the single digits 6, 4, 8, 5 and 6, 3 and 7, 5 and 7, 3 and 11, 2 and 11. Two identical single digits must be divided into two different groups
So the final answer is 6, 35, 33, 8, and the rest is another group

A = {1 / 6,1 / 12.1/20,1 / 30,1 / 42}, B = {1 / 8,1 / 24,1 / 48,1 / 80} take a number from each group and multiply to get a product,
What is the sum of all these 20 products?

Because (a1 + A2 +...) +an)(b1+b2+…… +The sum of these 20 products is: (1 / 6 + 1 / 12 + 1 / 20 + 1 / 30 + 1 / 42) x (1 / 8 + 1 / 24 + 1 / 48 + 1 / 80) = (70 / 420 + 35 / 420 + 21 / 420 + 14 / 420 + 10 / 420) x (30 / 240 + 10 / 2)

What is the number of the sum of the product of 25 4 times and 24 3 times?

Tvceng, Hello: 1 4, 4 bits; 2 4 multiplied by 16, 6 bits; 3 4 multiplied by 64, 4 bits; 4 4 multiplied by 256, 6 bits Every time the odd number of 4 is multiplied, the bits are always 4, so the product of 25 4 multipliers has 4.1 3 bits and 3 bits; 2 3 multiplies 9 bits and 9 bits; 3 3 multiplies 27 bits

The product of three multiplications is 720, the product of the first number and the second number is 9, and the product of the second number and the third number is 240

The third number is 720 △ 9 = 80
The first number is 720 / 240 = 3
So the second number is 9 / 3 = 3

If a number is multiplied by 4 and 9 respectively, the sum of the products is 2782. What is the number? How to solve it

2782÷(4+9)=214
That is 214

What number is the product of 98 nines?

Multiplying two nines by one digit is one
Multiplying three nines by one digit is nine
Four nines multiply by one
Five nines multiplied by one digit is nine
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So even nine times one bit is one
So 98 nines are multiplied by 1

If one factor increases by 1.3, the product increases by 9.1; if the other factor decreases by 3, the product decreases by 5.7. What is the sum of the two numbers?

9.1 / 1.3 = 7. Another factor is 7
5.7 / 3 = 1.9. One factor is 1.9
So their sum is 1.9 + 7 = 8.9

The product of a number multiplied by 12 is 45 more than the product of a number multiplied by 9. What's the number

This number is 45 (12-9) = 15

There is a two digit number. The sum of the numbers in the product obtained by multiplying this two digit number with one of the numbers from 1 to 9 is equal to the sum of the numbers of this number, and the two digits can be obtained
There are 18, 45, 90, 99 processes

First of all, the sum of the digits of the multiple of 9 must be the multiple of 9. For example, 3456 is the multiple of 9, 3 + 4 + 5 + 6 = 18 is also the multiple of 9, 123456789 is the multiple of 9, 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45 is also the multiple of 9, and the sum of the two digits multiplied by 9 must be the multiple of 9, so the number must be the multiple of 9

Divide the numbers 4, 6, 8, 21.22, 30 and 35 into two groups so that the product of the four numbers in each group is equal