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Mark application questions (clear process) 1. The ratio of salt to water in one bottle of brine is 1:4, and the concentration of the other bottle of brine is 10%. After mixing two bottles of brine, the concentration is 12%. What is the weight ratio of the two bottles of brine? 2. 200 grams of 10% salt water and 20 grams of 20% salt water are mixed, and the concentration becomes 12%. How many grams of salt water are mixed? 3. When a commodity is sold at its original price, it can make a profit of 25%. Later, when the cost rises, it will raise the price by 20%, and it can only make a profit of 20%. How much does the cost rise?
The concentration of the first bottle is 1 ÷ (1 + 4) = 1 / 5, the concentration of the second bottle is 10%, and the mixed concentration is 12%. According to the idea of average problem, the mass ratio of two bottles is (12% - 10%): (1 / 5-12%) = 1:4. The mass ratio of 10% brine and 20% brine is (20% - 12%): (12% -...)
Score calculation (complete process)
7 and 3 / 7 × 8 / 39
1 1 / 3 1.4 1 / 7
1 / 2 + (11.7 + 8.4 × 1 and 3 / 10) △ 1 and 3 / 10
1 and 1 / 3 / 2 and 2 / 5 / 1 and 1 / 7
1 × 5.3 + 0.125 × 4.7
7 and 3 / 7 × 8 / 39
=52/7×8/39
=32/21
1 1 / 3 1.4 1 / 7
=4/3×5/7×7/8
=5/6
1 / 2 + (11.7 + 8.4 × 1 and 3 / 10) △ 1 and 3 / 10
=1/2+（11.7+8.4×13/10）×10/13
=1/2 + 11.7×10/13 + 8.4
=1/2 + 9 + 8.4
=17.9
1 and 1 / 3 / 2 and 2 / 5 / 1 and 1 / 7
=4/3×5/12×7/8
=35/72
1 × 5.3 + 0.125 × 4.7
=1/8×5.3+0.125×4.7
=1/8×10
=1.25
How to do score calculation
7.8 - (2.8 + 3 and 5 / 7)=
5.2 × 3 / 8 + 4.625 × 5 and 1 / 5=
※1-3/8÷3×2/3=
※8÷2/11×125%=
7.8 - (2.8 + 3 and 5 / 7) = (7.8-2.8) - 3 and 5 / 7 = 5-3 and 5 / 7 = 1 and 2 / 7 5.2 × 3 / 8 + 4.625 × 5 and 1 / 5 = 26 / 5 × 3 / 8 + 37 / 8 × 26 / 5 = 26 / 5 × (3 / 8 + 37 / 8) = 26 / 5 × 5 = 26 1-3 / 8 △ 3 × 2 / 3 = 1-3 / 8 × 1 / 3 × 2 / 3 = 1-1 / 8 × 2 / 3 = 1-1 / 12 = 11 / 12 8 △ 2 / 11 × 125 ℅ = 8 × 11 / 2 ×
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