How to calculate the 2 / 3 power of 9?

9^(2/3)
=[3]√(9^2)
=[3]√81
=3×[3]√3
This is the power of the fractional exponent,
In general, there is a formula that can be used:
A ^ (M / N) = the nth root of a ^ m

Calculation: the third power of 10 + (- 1 / 30) - the power of - 2 * (- 600) - the third power of (- 3) * the - 1 power of 0.3 * the power of 0

Power 3 of 10 + power 0 of (- 1/30) -2 * power 0 of (-600) - power 3 of (-3) *0.3 power -1 * power 0
=1000+900*1-(-27)*10/3*1
=1000+900+90
=1990

Given that the a power of 10 = 50, the B power of 10 = the - 1 power of 2, how much is the value of a power of 9 △ 3 of 2B power,

The a power of 10 = 50, the B power of 10 = the - 1 power of 2
A power of 10 / B power of 10 = 50 * 2 = 100
10^(a-b)=10^2
a-b=2
A power of 9 △ 2B power of 3
=9^(a-b)=9^2=81

Given that the a power of 10 = 20, the B power of 10 = the negative first power of 5, find the value of a power of 9 + the 2B power of 3

10^a=20lg10^a=lg2*10a=lg2+lg10=lg2+110^b=5^(-1)lg10^b=lg5^(-1)b=-lg59^a+3^2b=9^a+9^b=9^(lg2+1)+9^(-lg5)=9*9^lg2+1/9^lg5=(9*9^lg2*9^lg5+1)/9^lg5=(9*9^(lg2+lg5)+1)/9^lg5=(9*9^lg10+1)/9^lg5=(9*9+1)/9^lg5...

If the a power of 10 is 20 and the B power of 10 is 0.5, find the a power of 9 divided by the 2B power of 3 Can't understand

0

[(- 3)'s 2nd power - 2's power - (- 5)'s 2nd power] * 5 / 6 / 4 / 9 * (- 2)'s 4th power
=[9-4-25]*5/6/4/9*16
=-20*5/6/4/9*16
=-50/3*9/4*16
=-75/2*16
=-600
The third power of [- 1 / 3 * (- 1 / 2) + (- 1 / 9) / 2 / 3] / (- 2)
=[1/6-1/6]/9
=0/9
=0

The second power of 2-2 -- the third power of 2-The fourth power of 2-2-the fifth power of 2-2-the sixth power of 2-2-the eighth power of 2-2-the ninth power of 2-2 + the 11th power of 2 The 2008 power of - 2 + the 2009 power of 2

The second power of 2-2 -- the third power of 2-2, the fourth power of 2-2, the fifth power of 2-2, the seventh power of 2-2, the eighth power of 2-2, the tenth power of 2-2, the 2008 power of, and the power of 2009 of 2
Let a = 2-2's quadratic power -- 2's cubic power - 2's fourth power - 2's quintic power -,,,,, - 2's 2008 power + 2's 2009 power
The power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A, the power of - 2 A
2a-a = 2's quadratic power-2 + 2's quadratic power-2's 2009 power - 2's 2009 power + 2's 2010 power
=The quadratic power of 2 + 2 - the 2009 power of 2 + 2 + the 2010 power of 2
=6
The original formula = 6

How much is the 12th power of (- 0.125) multiplied by (- 1 and 2 / 3) by the 7th power of (- 8) and the 13th power of (- 3 / 5)

(-0.125)^12*[-1(2/3)]^7*(-8)^13*(-3/5)^9
=(-1/8)^12*(-5/3)^7*(-8)^13*(-3/5)^9
=(1/8)^12*(5/3)^7*8^13*(3/5)^9
=(1/8)^12*8^12*8*(5/3)^7*(3/5)^7*(3/5)*2
=8*(3/5)^2
=8*(9/25)
=72/25

(1 and 7 / 9) to the 11th power (9 / 16) to the 11th power (- 1) to the 11th power

Hello!
(1 and 7 / 9) to the 11th power (9 / 16) to the 11th power (- 1) to the 11th power
=-(16 / 9) to the 11th power (9 / 16) to the 11th power
=-The 11th power of (16 / 9x9 / 16)
=-The 11th power of 1
=-1
If there is something you don't understand, you can ask it. If you are satisfied, remember to adopt it
If you have any other questions, please accept this question and send it to me for help
Wish you progress!

(- 5 of 8) divided by 1 and 9 of 16 - (1 and 1 of 8) * - 2 of 3) {(1 of 6-4) * 12} + 2004

Hello: (- 5 / 8) divided by 1 / 16 9 - (1 / 8 / 1) * (- 2 / 3) + {(1 / 4 of 6) * 12} + 2004 = 25 / 64 ＋ 25 / 16-9 / 8x4 / 9 + (- 1 / 12x12) 2 + 2004 = 1 / 4-1 / 2 + 1 + 2004 = 2004 and 3 / 4

How to calculate the 2 / 3 power of 9?