11 + 11 squared + 11 cubic +. + 11 2002 power how to calculate?

X = 11 + 11 squared + 11 cubic +. + 11 2002 power
11x = the square of 11 + the cubic power of 11 +. + 2002 power of 11 + 2003 power of 11
11x-x = 11 to the 2003 power - 11
X = (2003 power of 11 - 11) / 10

To the power of (2003) as soon as possible

The 2003 power of 0.04 is multiplied by the square of (- 5)
=0.04 to the 2003 power multiplied by (25 to the 2003 power)
=The 2003 power of 1
=1

Calculation: the power of (n + 1) of 1-2 + 3-4 + 5-6 +... (- 1) is multiplied by n

When n is odd, there are 1-2 + 3 + 3-4 + 5-6 + 6 +... + (- 1) ^ (n + 1) * n = 1-2 + 3 + 3-4 + 4 + 5-6 + 6 +... + n because (1-2 + 3-4 + 5-6 + 6 + n) + (1 + 2 + 3 + 4 + 5 + 6 + 6 +... + n) = 2 (1 + 3 + 5 + 5 + 6 + 6 +... + n) = 2 (1 + 3 + 5 + 5 + 6 + n) (n + 1 + 1) / 2 = 2 * (n + 1) / 2) / 2 = (n + 1) 2) / 2 = (n + 1) 2) / 2 = 1-2 + 3-4 + 5-6 + 6 + n = (n = (n = 1 + 1 + 1 + 1 + 1 + 1 + 1 + N + 1) 2 / 2 -

Calculation: the N + 1 power of 1-2 + 3-4 + 5-6 +. + (- 1) times the value of n

If n = 2K, then n is even
The original formula = (1-2) + (3-4) +... (n-1-n)
=-n/2
When n = 2K + 1, n is odd
The original formula = (1-2) + (3-4) +... [n-2 - (n-1)] + n
=-(n-1)/2+n
=(n+1)/2

Calculate the N + 1 power of 1-2 + 3-4 + 5-6 +. + (- 1) times the value of n

n=2k,
The original formula = (1-2) + (3-4) +... (n-1-n)
=-n/2
n=2k+1
The original formula = (1-2) + (3-4) +... [n-2 - (n-1)] + n
=-(n-1)/2+n
=(n+1)/2

The N + 1 power of 1-2 + 3-4 + 5-6 +. + (- 1) is multiplied by n

When n is an even number, the last term is negative, that is, 1-2 + 3-4 + 5-6 +. + (n-1) - n = (1-2) + (3-4) + (5-6) +. + (n-1-n) = - N / 2

The fourth power of 2 is multiplied by the fourth power of three times five, and is calculated by multiplying the product of powers

2^4*3*5^4=(2*5)^4*3=3*10^4=30000

The second power of 1.99.9 and 2.201 can be easily calculated Simple calculation of the second power of 1.99.9 The second power of 2.201 Given that: [M-N] to the 2nd power = 8, find 1. [M + n] to the 2nd power; 2. M to the 4th power + n to the 4th power : the 2nd power of [M-N] is 8, Mn is 8, and the 2nd power of 1. [M + n] is obtained; the 4th power of 2. M + n is evaluated to the 4th power of n

99.9^2=(100-.01)^2=10000+0.01-2*0.1*100=9980.01;
201^2=(200+1)^2=40000+1+2*200*1=40401;
If [m-n) ^ 2 = 8, Mn = 8, then m ^ 2 + n ^ 2-2mn = 8, m ^ 2 + n ^ 2 = 24, (M + n) ^ = 24 + 16 = 40;
m^4+n^4=(m^2+n^2)^2-2(mn)^2=24*24-**64=448

Find the number of bits of (2-1) (2 + 1) (the square of 2 + 1) (the fourth power of 2 + 1)... (the 32nd power of 2 + 1) + 1 A hundred points is your answer In fact, it is the sixth question on page 57 of the first grade mathematics book of Beijing model edition

(2-1) (2 + 1) (the square of 2 + 1) (the fourth power of 2 + 1) (the 32nd power of 2 + 1) + 1 = (the square of 2 - 1) (the square of 2 + 1) (the fourth power of 2 + 1) (32nd power of 2 + 1) + 1 = (4th power of 2 - 1) (4th power of 2 + 1) (32 power of 2 + 1) + 64 power of 1 = 2 - 1 + 6 of 1 = 2

11 + 11 squared + 11 cubic +. + 11 2002 power how to calculate?