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The 12th power of 2 - the 11th power of 2 - the 10th power of 2 - the 9th power of 2 - the 8th power of 2 - the 7th power of 2 - the 6th power of 2
=4096-2048-1024-512-256-128-64
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Xiaohong wants to know the length of the bundle of wires. She chooses a short wire of the same specification and material to indirectly measure the length of the bundle of wires. The length of the short wire is 1m and the mass is 0.178kg (1) The total length of the wire is L; (2) The density of the wire is ρ

(1) The results show that the total length of wire: l = m total m × 1m = 8.9kg0.178kg × 1m = 50m; (2) the total volume of wire: v = SL = 2 × 10-5m2 × 50m = 1 × 10-3m3; the density of wire: ρ = mtotal v = 8.9K

The length of the wire is about 10-2.5 kg, Xiaohong wants to know the length of the bundle of wires. She chooses a short wire of the same specification and material to indirectly measure the length of the bundle of wires. The length of the short wire is LM and the mass is 0.178kg The density of the wire is ρ

If the length of the wire is known, the volume can be calculated and the density can be obtained. If the mass of the wire is 0.178kg, the mass of the wire is 8.9kg? L = (8.9 / 0.178) × 1 = 50mV = SL = 2 × 10 ^ (- 5) × 50 = 1 × 10 ^ (- 3) m 3 ρ = m / v = 8.9kg / 1 × 1

Xiaohong wants to know the length of the bundle of wires. She chooses a short wire of the same specification and material to indirectly measure the length of the bundle of wires. The length of the short wire is LM and the mass is 0.178kg (1) The density of the wire (2) The total length of the bundle of metal

（1）ρ=m／v=m／s·L=0.178kg／2×10-5m2×lm=8.9×10-3㎏／m2
(2) From ρ = m / v = m / s · L, 8.9kg/Χ = 0.178kg/1m, the solution is: Χ = 50m
Therefore, the density of wire is 8.9 × 10-3 kg / m2 and the total length of metal is 50 m

Xiaohong wants to know the length of the bundle of wires. She chooses a short wire of the same specification and material to indirectly measure the length of the bundle of wires. The length of the short wire is 1m and the mass is 0.178kg (1) The total length of the wire is L; (2) The density of the wire is ρ

(1) The results show that the total length of wire: l = m total m × 1m = 8.9kg0.178kg × 1m = 50m; (2) the total volume of wire: v = SL = 2 × 10-5m2 × 50m = 1 × 10-3m3; the density of wire: ρ = mtotal v = 8.9K

The mass is 3.0 × 10 cubic kilogram, the density is 1.5 × 10 cubic kilogram per cubic meter, and the contact area with the horizontal ground is 1 square meter

(1) Volume = 1000
(2)m=ρv=4.5×1000kg=4500kg
(3) The pressure is p = f / S = mg / S = 45000pa

How to calculate the negative octave of 10, and what is his arithmetic square root,

The answer is 1 / 10000000
8 zeros after 1
The arithmetic root is positive. It is 1 / 10000

The square root of minus 6 of 10 Format: ∵ (± x) 2 = a ᙽ the square root of a is ± x, that is: √ (a) = ± X

∵ (± 10 to the negative third power)  = 10 to the negative 6th power  to the square root of the negative sixth power of 10 to the negative third power of ± 10
That is √ (10 to the negative sixth power = ± 10 to the negative third power)

What is the arithmetic square root of minus 2 of 10

The - 2 power of 10 is one part of the square of 10
So its arithmetic square root is 1 / 10

There is a polynomial which is the 10th power of a - the 9th power of a + the 8th power of a, the square of B - the 7th power of a, and the third power of B 1. Write the sixth and last item

Its sixth term: - the fifth power of a and the fifth power of B
The last term: the 10th power of B