What is the 99 th power of (- 2) + the 98 th power of (- 2) + + (- 2) to the 97 th power

What is the 99 th power of (- 2) + the 98 th power of (- 2) + + (- 2) to the 97 th power

The 97th power of 3 (- 2)

What is the 99 th power of 2 times the 100 th power of minus 1 / 2 Is: what is the 99 th power of 2 multiplied by the 100 th power of minus 1 / 2?

99 2 times 99 1 / 2 equals 1 and there is 1 / 2 left

What is the 99 th power of 2 × 100 th power of negative 1 / 2 fast

0

0

The 99th power of 2 × the 100th power of minus 1 / 2
=The 99th power of 2 × the 99th power of minus 1 / 2 × (- 1 / 2)
=(-1/2×2)^99×(-1/2)
=(-1)^99×(-1/2)
=1/2

What is the 100th power of 3 x the 99th power of (minus one third)?

To the 100th power of 3 × (minus one third) to the 99th power
=The 99th power of 3 × 3 × (minus one third)
=99 power of 3 × (3 × minus 3)
=The 99th power of 3 × (minus 1)
=Minus 3

To the power of 100 to the power of 7?

The 99th power of 0.5 times the 100th power of 2 = (0.5 × 2) to the 99th power × 2 = 1 × 2 = 2
The 7th power of (1 in 7) times the 4th power of 49 = (1 in 7) times the 8th power of 7 = (1 in 7 times 7) times 7 = 1 times 7 = 7

Let a = 9 to the 99th power to the 99th power and B = 9 to the 90th power to the 9th power to the 11th power Is: let a = 9 to the 99th power to the 99th power and B = 90 to the 9th power to the 11th power, then the size relationship between a and B is

equal.
Because a / b = 1
There are many ways to compare sizes:
If it is more than 1, then a > b; B;

Let a be equal to the 99th power of 9 and the 9th power of 11, and B be equal to the 9th power of 90 and the 9th power of 11. Compare the size of ab Let a be equal to the 99th power of 9 to the 9th power of 99, and B to the 9th power of 11th power of 90, and compare the size of ab.

a=99^9/9^99=(9x11)^9/9^99=(9^9x11^9)/9^99=11^9)/9^90
b=11^9/90^9
The numerator of a is the same as that of B, and the larger denominator is, the smaller the value is. Just compare the size of 9 ^ 90 and 90 ^ 9
And 9 ^ 90 = (9 ^ 10) ^ 9 = (81 ^ 5) ^ 9
It can be seen that (81 ^ 5) > 90, that is, 9 ^ 90 > 90 ^ 9
∴a<b

If a = the 9th power of 99 / the 99th power of 9, and B = the 9th power of 11 / the 90th power of 9, then a________ b.

A=b
a/b=(99^9 /9^99) / (11^9 / 9^90)
=(99^9 X 9^90) / (9^99 X 11^9)
=99^9 / 9^9 X 11^9
=99^9 / (9X11)^9
=99^9 /99^9
=1
So a = B

The third power of a plus the third power of B is equal to the third power of? (a + b) is equal to? The third power of a minus the third power of B is equal to? The third power of (a-b) is equal to?

1. The third power of a and the third power of B is equal to?
a³+b³=(a+b)(a²-ab+b²)
The third power of (a + b) is equal to?
(a+b)³=a³+3a²b+3ab²+b³
3. The third power of a minus the third power of B is equal to?
a³-b³=(a-b)(a²+ab+b²)
The third power of (a-b) is equal to?
(a-b)³=a³-3a²b+3ab²-b³