6 to the third power of Radix 6 (accurate to 0.01)

6 to the third power of Radix 6 (accurate to 0.01)

6^(1/3) = 1.8171205928321
The 1 / N power of n-th root sign a = a
Is it not good to use the calculator that comes with the system?

If the second power of (2a + 3) and the root sign B + 2 are opposite to each other, find the value of a + B

(2a + 3) ^ 2 and radical B + 2 are both nonnegative numbers
But they are opposite to each other
So they must all be zero
So = - 2 = - 2
a+b = - 7/2

How to compare the square root of 0.2 with the power of 0.2? Who is bigger?

0.2^√22^0=1
∴2^0.2>0.2^√2

Using cos α to express sin α (quartic) - sin α (quadratic) + cos α (quadratic)

0

0

sin^2a=tan^2a/(1+tan^2a)=9/10
(3/4)sin^2α+(1/2)cos^2α=1/2+1/4sin^2a=1/2+1/4*9/10=29/40
sinαcosα=sin^2a/tana=9/10/3=3/10

If 0 ° < α < 90 ° and the square of | sin α - 1 / 4 | + (COS α - radical 3 / 2) = 0, then the value of Tan α? If 0 ° is less than α < 90 ° and the square of | sin α - 1 / 4 | + (COS α - root 3 / 2) is 0, then the value of Tan α?

From what is known,
(sinα)^2=1/4,cosα=√3/2.
So α = 30 degrees or - 30 degrees, and 0 degrees < α < 90 degrees,
Therefore, α = 30, Tan α = √ 3 / 3

Given Tan α = 3, find the square of (sin α + cos α). Given Tan α = - 1 / 3, find: 1 / 2 sin α cos α + cos square α

1. Sin α = 3 √ 10 / 10 cos α = √ 10 / 10 (sin α + cos α) squared = 8 / 52, cos square α = 1 / Tan square α = 91 / 2Sin α cos α + cos square α divided by cos square α, then multiplied by cos square α = cos square α [(1 / 2Sin α cos α + cos square α) / cos square α] = cos square α (1 /...)

Given sin (X-Y) cosx cos (X-Y) SiNx = three fifths, find the value of tan2y

Sin (X-Y) cosx cos (X-Y) SiNx = sin [(X-Y) - x] = sin (- y) = - siny = 3 / 5siny = - 3 / 5sin? Y + cos? Y = 1, so cos? Y = 16 / 25cosy = 4 / 5 or - 4 / 5tany = siny / cosy = - 3 / 4 or 3 / 4tan2y = 2tany / (1-tan? Y) = ± (3 / 2) / (1-9 / 16) = ± 8 / 3

Given SiNx + cosx = 2 / 3, find the value of sin ^ 4 + cos ^ 4

SiNx + cosx = 2 / 3 both sides are squared at the same time to get sin? X + 2sinxcosx + cos? X = 4 / 91 + 2sinxcosx = 4 / 92sinxcosx = - 5 / 9sinxcosx = - 5 / 18 (SiNx) ^ 4 + (cosx) ^ 4 = [(SiNx) 2 + (cosx)?)] - 2 (sinxcosx) 2 = 1? - 2 × (- 5 / 18) mm2 =

Sin (x + y) cosx + cos (x + y) SiNx = 1 / 3 x ∈ (3 π / 2,2 π) find cos (2x + π / 4)

X ∈ (3 π / 2,2 π) so 2x ∈ (3 π, 4 π) formula = sin (2x + y) = 1 / 3, that is, 2x + y is under 3 / pie, or below 2 Pai / 3 and above the X axis
If the original formula = sin (2x + y) = 1 / 3, then cos (2x + y)=
Cos (2x + π / 4) = (1 / Radix 2) * cos2x + (1 / Radix 2) * sin2x