F (x) is equal to the x power of 2 minus the x power of 4

F (x) is equal to the x power of 2 minus the x power of 4

Solution: F '(x) = (2 ^ x) LN2 - (2 ^ (2x + 1)) LN2. Where 4 ^ x is replaced by 2 ^ 2x
Let f '(x) = 0 to get: 2 ^ X-2 ^ (2x + 1) = 0, so: 1 = 2 ^ (x + 1), that is, x = - 1
Because f (x) has no boundary, there is only one maximum value: F (- 1) = 1 / 4

Note: 3-x is the negative x power of 3. Then the whole minus 1

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0

Let t = e ^ x (T > 0)
Y = (t-1) / (T + 1) = 1-2 / (T + 1), so the range of Y is (- 1,1)

The value range of the function y = e to the power of x minus 1 divided by x plus 1 of e

(e^x-1)/(e^x+1)?
1-2/(e^+1)
(-1,+1)

What is the value range of the function y = x to the second power minus three divided by the second power plus one of X?

y=(x^2-3)/(x^2+1)=(x^2+1-4)/(x^2+1)=1 - 4/(x^2+1)
Because x ^ 2 + 1 > = 1
So 0

When x belongs to the closed interval - 2 ～ 0, the value range of x plus first power minus two of function y = 3 is

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You can do this problem according to the function image. First draw the x power image of y = 2. According to the left plus right minus, up plus down subtraction, the image moves one unit to the left, and then moves up two units to get the function

The definition domain and value domain of y = A's x power-1 / A's x power + 1

Since + T = 0.1, let + T = 1

Find the range of x power + 1 of y = 2 It's better to have specific steps

y=2(x^2--1/4+1/64-1/64)
=2(x-1/8)^2-1/32
So the minimum value of the function is - 1 / 32, and there is no maximum value
So the range is [- 1 / 32, + ∞)

What is the value range of y = 2 to the x power + 2 to the negative x power of 2

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