Given that the x power of 1 / 2 ≤ 2 is less than the x-3 power of (1 / 4), the value range of function y = 9 to the power of X-2 × 3 + 5 is obtained

Given that the x power of 1 / 2 ≤ 2 is less than the x-3 power of (1 / 4), the value range of function y = 9 to the power of X-2 × 3 + 5 is obtained

y=(3^x)^2-2*3^x+5=(3^x-1)^2+4
from
1/2≤2^x≤（1/4）
have to
-2≤x≤-1

Function, y = (3 times the x power of 2-5) divided by the range of (x power of 2 + 3)

Let a = 2 ^ X
Then a > 0
y=(3a-5)/(a+3)
=(3a+9-14)/(a+3)
=3-14/(a+3)
a+3>3
So 0 < 14 / (a + 3) < 14 / 3
-14/3<-14/(a+3)<0
3-14/3<3-14/(a+3)<3+0
The range is (- 5 / 3,3)

Given that the function y is equal to the second power of (1 / 3) x plus the power of 2x + 5, find its monotone interval and range of values (x ^ 2 + 2x + 5) this is y to the power of one third, and then help me find it

y=1/3^(x^2+2x+5)=1/3^[(x+1)^2+4]
Monotone increasing interval: (- ∞, - 1]
Monotone decreasing interval: [- 1, + ∞]
Range: (0,1 / 81]

The value range of y = a to the x power (a > 0) is It is written in the book that after the negative sign is raised, the function becomes two forms: So the range y is not equal to 0 Why should I mention that the power X of minus sign.A>0.A is greater than zero no matter whether X is positive or negative? Is it a Book fault or mine

a> 0, the x power of a must be greater than 0

Y is equal to 4 x power minus 3 times 2 x power plus 3, the definition domain is (- ∞, 0] ∪ [1,2], find the value range of function 【1,7】 I do it myself Right?

The definition domain is (- ∞, 0] ∪ [1,2], and find the value range of function
Let the x power of 2 = t 0

What is the value range of the function y = 4x power + 1 / 4x power?

y=1-1/(4^x+1)
4^x>0
Zero

Find the value range of X-1 power-5 of X-2 of function y = 4

The X-1 power of function y = 4-2 = (2 ^ x) ^ 2 - (2 ^ x) / 2-5 = (2 ^ X-1 / 4) ^ 2-81 / 16
When x = - 2, there is a minimum of - 81 / 16
The range is [- 81 / 16, + ∞)

0

y=4^x-3*2^x+3=(2^x)^2-3*2^x+3
y-1=(2^x)^2-3*2^x+2=(2^x-1)(2^x-2)>=0
=>2 ^ x < = 1 or 2 ^ x > = 2 = > x < = 0 or x > = 1
y-7=(2^x)^2-3*2^x-4=(2^x-4)(2^x+1)<=0
=> 2^x<=4 => x<=2
Therefore, the value range of X is (- infinite, 0] u [1, 2], and D is selected

How to find the range and monotone interval of the function y = (1-2 x power) / 4 x power

y=(1-2^x)/(2^x)^2=[(1/2)^x]
Let's see the picture
 

The value range of function y = 2 to the power of X + (2 to the power of - x) on the interval [1,3]

Cause 1=