(3x / x-1-x / x + 1) × x? - 1 / x where x = radical 2-2 is reduced first

(3x / x-1-x / x + 1) × x? - 1 / x where x = radical 2-2 is reduced first

The original formula = {[3x (x + 1) - x (x-1)] / (x-1) (x + 1)} * (x-1) (x + 1) / X
=[3x (x + 1) - x (x-1)] / x = (3x square + x-x square + x) / x = 2x + 4
When x = radical 2-2
Original formula = 2x + 4 = 2 (root 2-2) + 4 = 2 times root 2-4 + 4 = 2 times root 2

Simplify the evaluation, (3x / x-1-x / x + 1) / X / x2-1, where x = radical 2-2

[3x / (x-1) - X / (x + 1)] / X / (x? - 1) = [3x / (x-1) - X / (x + 1)] * (x? - 1) / x = [3x / (x-1)] * (x? - 1) / X - [x / (x + 1)] * (x? - 1) / x = 3 (x + 1) - (x-1) = 3x + 3-x + 1 = 2x + 4 = 2 (root 2-2) + 4 = 2 root 2-4 + 4 = 2 root 2

Reduction evaluation (2 / 3x radical (9x) + radical (4xy)) - (cube of radical x + radical (25xy)), x = 1 / 2, y = 3

Original formula = x √ x-3 √ (XY)
Substituting value = √ 2 / 4-3 √ 6 / 2

Simplify and then evaluate: 2 (3x-5) + (x-3) ^ 2, where x = radical 2 + 1

0

(3x / X-1 -- X / x + 1) x x x Square-1 / x where x = root 2-2 Write the process clearly Thank you````

=[3x(x+1)-x(x-1)/(x-1)(x+1)]x*x-1
=[2x*x+4x/(x-1)(x+1)]x*x-1
=[2x(x+1)+2x/(x-1)(x+1)]x*x-1
=(4x/x-1)(x+1)(x-1)
=4x(x+1)
=4X square + 4x
Put x = radical 2-2 in
=4 * 2-4 root number 2 + 4 + 4 root number 2-8
=0

Is it possible to estimate the square root and cube root? Are there any formulas and laws?

It's not allowed to use computers in exams. You can estimate
I memorized the squares of 2-16 (regular and this is a common number)
For example, the root sign 3 1 ^ 2 = 1 2 ^ 2 = 4, so the root sign 3 is between 1 and 2, because there is a root sign 2 between 1 and 2
Therefore, the root 3 is closer to 2 and can be estimated to be between 1.5 and 2
In this way, the estimation is basically accurate

What is 0.8 root sign 0.174? What is 0.8 root sign 4? To talk about the calculation,

Let y = 0.8 ^ 0.174, take logarithm on both sides; LNY = 0.174ln (0.8); check the logarithm table and the opposition table to know the answer
The next question is the same

Reduction of radical (- 36) · 169 · (- 9)

=Root number 4 × 9 × 13 2 × 9 = root 2 × 13 × 9 = 2 × 13 × 9 = 234

Under the root sign (- 4) * 24 out of 9 * (- 169) * is the multiplier sign

First of all, minus minus minus sign 4 is the square of 2, and 169 is the square of 13. So, if you take the square root of these two numbers, 2 * 13 is equal to 26 24 / 9, the denominator 9 is 3 24 = 4 * 6, and the square root of 24 / 9 is 2, so the root of 24 / 9 is (2 / 3) * 6 under the root sign, and then multiply by the previously opened 26 to get (52 / 3) * 6 under the root
It's a pity that negative sign can't be called. I can only give you the answer. I hope you can understand

What is root 405 after simplification

√405=√5*81=9√5