How many points are there on the circle x? Y? 2 + 2x + 4y-3 = 0 with a distance of 3 √ 2 from the straight line x + y + 1 = 0?

How many points are there on the circle x? Y? 2 + 2x + 4y-3 = 0 with a distance of 3 √ 2 from the straight line x + y + 1 = 0?

Circle (x + 1) 2 + (y + 2) 2 = 8
The center of the circle (- 1, - 2), radius r = 2 √ 2
The distance from the center of the circle to the straight line d = | - 1-2 + 1 | / √ 2 = √ 2
2r-d=3√2
There is only one

(2014. Changan District three mode) circle: the maximum distance from point to straight line x-y=2 on x2+y2-2x-2y+1=0 is () A. 2 B. 1+ Two C. 1+ Two Two D. 1+2 Two

The circle x2 + y2-2x-2y + 1 = 0 can be reduced to the standard form: (x-1) 2 + (Y-1) 2 = 1,
The center of the circle is (1, 1), and the radius is 1
The distance from the center of a circle (1, 1) to the straight line X-Y = 2 D =
2，
Then the maximum distance is 1+
2，
Therefore, B

2x+6=3+x 4-3x=3-2x x-1/2=-1/2x+2 -x/3=2x-7/3 2x+6=3+x 4-3x=3-2x x-1/2=-1/2x+2 -x/3=2x-7/3

(1) 2x+6=3+x
2x-x=3-6
x=-3
(2) 4-3x=3-2x
2x-3x=3-4
-x=-1
X=1
(3) x-1/2=-1/2x+2
x+1/2x=2+1/2
3/2x=5/2
x=5/3
(4) -x/3=2x-7/3
2x+x/3=7/3
7/3x=7/3
X=1

The formula 3x + (2x-x) = 3x + 2x-x, 3x - (2x-x) = 3x-2x + X What are the two equations you get from the reverse of each? 1. Comparing the equations you get, can you summarize the rule of parenthesis? 2. According to the bracketed rule you summarized above, do not change the value of the polynomial x ^ 3-3x ^ 2 + 3x-1 (1) In the bracket with "+"; (2) in the bracket with "+" before it

3x+2x-x=3x+(2x-x),3x-2x+x=3x-(2x-x)
1. The rule of adding brackets: the + sign is in front of the bracket, and the item symbol in the bracket remains unchanged; before the bracket is the - sign, the item symbol in the bracket should be changed;
2、（1）x^3-3x^2+3x-1=x^3-3x^2+(3x-1)
(2)x^3-3x^2+3x-1=x^3-3x^2-(-3x+1)

When x is the value, the value of the formula | 2x + 3 | and the value of 3x-1, which is quarter of the equation, are opposite to each other process

When x > - 3 / 2,
|2x+3|=2x+3
According to the meaning of the title, ν2x + 3 + (3x-1) / 4 = 0
----->8x+12+3x-1=0
----->11x=-11
----->x=-1>-3/2
So x = - 1 holds;
When x-8x-12 + 3x-1 = 0
---->5x=-13
---->x=-13/5

If the square of + 3x is the square of - 2x, then the square of + 2x is the square of - 2x? It is better to write the calculation process

3x^2-2x+6=8
3x^2-2x=2
(3/2)x^2-x+4=[3x^2-2x]/2+4=2/2+4=1+4=5

4 / 3x-5 / 2x = 8 / 7

4/3x-5/2x=8/7
8/6x-15/6x=8/7
-7/6x=8/7
x=-4/3

When x = (), the values of formula (2x-1) / 5 and formula (2x) / 3-5 are opposite to each other

(2x-1)/5+2x/3-5=0
3(2x-1)+2x*5-75=0
6x-3+10x-75=0
16x=78
x=39/8

How to solve this equation

3x-1/2=10
3x=10.5
x=3.5

4-5x is 2x + 3. When x is equal to what number, the fraction value is zero? When x takes what number, the fraction has no meaning? The process also needs to trouble you

When 2x + 3 = 0 and 4-5x! = 0, the fractional value is 0, so the fractional value is 0 when x = - 1.5
When 4-5x = 0, the fraction is meaningless, so the value of fraction is meaningless when x = 0.8