If the value of the algebraic expression 2x? - 3x + 2 is 7, what is the value of X? - 3 / 2x-1

If the value of the algebraic expression 2x? - 3x + 2 is 7, what is the value of X? - 3 / 2x-1

2x²-3x+2
=2（x²-3/2x）+2=7
x²-3/2x=5/2
x²-3/2x-1=5/2-1=3/2

Given the quadratic power of a = x-2x-3, B = 2x-5, C = 1 / 2x-7x-6, find 2A + b-4c

2A+B-4C =2(x^2-2x-3)+(2x^2-5)-4(1/2x^2-7x-6) =2x^2-4x-6+2x^2-5-2x^2+28x+24 =2x^2+24x+13

A = x squared-2x-3, B = 2x-5, C = 1 / 2 x-7x + 6 Find the value of a - (b-4c)

Let ^ 2 represent the square a - (b-4c) = A-B + 4C = x ^ 2-2x-3-2x ^ 2 + 5 + 2x ^ 2-28x + 24 = x ^ 2-30x + 26

By solving the fractional equation (5-2x) / (x ^ 2-x-12) = 5x / (x ^ 2 + X-6) + (10-7x) / (x ^ 2-6x + 8)

(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)
(5-2x)/(x-4)(x+3)=5x/(x+3)(x-2)+(10-7x)/(x-2)(x-4)
The denominator is multiplied by (x-4) (x + 3) (X-2)
(5-2x)(x-2)=5x(x-4)+(10-7x)(x+3)
That is - 2x ^ 2 + 9x-10 = 5x ^ 2-20x-7x ^ 2-11x + 30
9x-10=-31x+30
40x=40
X=1

Solve - 2x? - 6 = - 7x -2x²-6=-7x

-2x²-6=-7x
2x²-7x+6=0
(2x-3)(x-2)=0
X = 3 / 2 or x = 2

2X? 7x + 6 = 10, In addition: y = x + 2 1 / 2 root sign x, the value range of independent variable x

Shift: 2x? - 7x-4 = 0
Cross multiplication yields (2x + 1) (x-4) = 0
That is, 2x + 1 = 0 or x-4 = 0
So x = - 1 / 2 or x = 4
Is that 1 / 2 of the root x? If so, x > 0

X square - 4 times x square - 2x divided by (x-2-x + 2X-4 of 2, where x = 2 + root 2

The original formula = [(x? - 2x) / (x? - 4)] / [X-2 - (2X-4) / (x + 2)]
={x(x-2)/[(x+2)(x-2)]÷[(x-2)(x+2)/(x+2)-2(x-2)/(x+2)]
=[x/(x+2)]÷{[(x-2)(x+2)-2(x-2)]/(x+2)}
=[x/(x+2)]÷[(x-2)(x+2-2)/(x+2)]
=[x/(x+2)]÷[x(x-2)/(x+2)]
=[x/(x+2)]×{(x+2)/[x(x-2)]}
=1/(x-2)
=1/(2+√2-2)
=1/√2
=(√2)/2

Solution equation: 3 / 5x + 1 - 6 / 2x - 1 = 1

Multiply both sides by 6
2(5x+1)-(2x-1)=1
10x+2-2x+1=1
8x=-2
x=-1/4

Given the square of x-5x + 1 = 0, find the value of the square of X + the negative quadratic power of X It's in the mathematical "integral division" of the first grade of junior high school

We know that x 2 - 5x + 1 = 0, obviously x is not equal to 0,
Divide both sides by X at the same time to get: X-5 + (1 / x) = 0
That is: x + (1 / x) = 5
Square both sides at the same time
x²+2+(1/x)²=25
x²+(1/x)²=23
That is: the square of X + the negative quadratic of X is 23

Given that x 2-5x = 14, we can not understand the equation, simplify and find the value of formula (x-1) (2x-1) - (x + 1) 2 + 1

Original formula = 2x2-3x + 1 - (x2 + 2x + 1) + 1
=2x2-3x+1-x2-2x-1+1
=x2-5x+1，
∵x2-5x=14，
The original formula = 14 + 1 = 15