It is known that the solution of equation 2x AX = 3 is inequality 5 (X-2) - 7

It is known that the solution of equation 2x AX = 3 is inequality 5 (X-2) - 7

5（x-2）-7＜6（x-1）-8
5x－10－7＜6x－6－8
5x－17＜6x－14
－3 ＜ x,
∴ x＝－2,
∵2x-ax=3
（2－a）x=3
2－a＝－3／2
a＝7／2,
∴4a-（14/a）
＝4×7／2-（14×2／7）
＝14－4
＝10.

Given that x = - 1 is a root of the equation 2x ^ 2 + ax-a ^ 2 = 0 about X, then how much is a

2x^2+ax-a^2=0
2(-1)^2-a-a^2=-0
a^2+a-2=0
(a-1)(a+2)=0
A = 1 or a = - 2

The equation x ^ 2-3 / 2x-m = 0 has and only one root on (- 1,1)

X ^ 2-3 / 2x-m = 0 has and only one root on (- 1,1)
f(-1)*f(1)

It is known that one root of the equation 2x square + 3mx + m square = 0 is x = 1. Find the value of M and the other root of the equation

One root of the equation 2x of X + 3mx + M2 = 0 is x = 1
Then 2 * 1? 2 + 3M + M2 = 0
Then M 2 + 3 M + 2 = 0
(m+2)(m+1)=0
M = - 2 or M = - 1
When m = - 2, the equation is 2x? - 6x + 4 = 0, (2x-2) (X-2) = 0, then x = 1 or x = 2, so the other root is x = 2
When m = - 1, the equation is 2x? - 3x + 1 = 0, (2x-1) (x-1) = 0, then x = 1 or x = 1 / 2, so the other root is x = 1 / 2

If one root of equation 2x ^ 2 + X + M = 0 is 1, then the other root is

analysis,
X = 1 generation 2x ^ 2 + X + M = 0,
M = - 3,
Therefore, the equation is 2 x 2 + x-3 = 0
X = 1 or - 3 / 2
So the other one is - 3 / 2

It is known that the one variable quadratic equation 2x 2 + 4x + M = 0 about X. if x = 1 is a root of the equation, it needs a process to find another following of the equation. Please Given that the quadratic equation of X is 2x 2 + 4x + M = 0, find the second question. If X1 and X2 are two different real roots of the equation, and satisfy the requirements of X1 2 + x2 2 + 2x1x2 - X1 x2 = 0, find the value of M

b²－4ac＝16－8m≥0m≤2x1＋x2＝﹣2,x1·x2＝m/2∵ x1²＋x2²＋2x1·x2－x1²x2²＝0∴ ﹙x1＋x2﹚²－﹙x1x2﹚²＝04－m²/4＝0m²＝16m±4∵ m≤2∴ m＝﹣4....

The solution of the equation 2x + 3 = M-1 of X is the same as that of 3x-2m = x + 4

2x+3=m-1 2x=m-4 x=(m-4)/2
3x-2m=x+4 2x=2m+4 x=m+2
According to the meaning of the title:
m+2=(m-4)/2 2(m+2)=m-4 2m+4=m-4
∴ m=-8

If the solution of equation 2 (2x-3) - 1 = 1-2x is also the solution of equation 8-K = 2 (x + 1) about X, find the value of K

4x-6-1=1-2x
6x=8
x=4/3
8-k=2(x+1)
x=4/3
So 8-K = 14 / 3
k=8-14/3
k=10/3

If the equation 2x-3 = 1 and x-k for X 2 = k-3x, if the solutions are opposite to each other, then k = 0___ .

Firstly, the equation 2x-3 = 1 is solved to obtain x = 2;
Put x = - K into the equation
2 = k-3x, resulting in: - 2-k
2=k+6；
The solution is: k = - 14
3．
Therefore: - 14
3．

If the equation (K + 2) x square – 2x + k = 0 has a root of - 1, then K is equal to

Put x = - 1 into the equation
(k+2)×（-1）²-2×（-1）+k=0
k+2+2+k=0
2k+4=0
2k=-4
k=-2