It is known that the square of 2x minus 4x plus 3Q is equal to one root of 0, which is 1 minus the root sign 2. The process of finding another root of X and the value of Q is also necessary

It is known that the square of 2x minus 4x plus 3Q is equal to one root of 0, which is 1 minus the root sign 2. The process of finding another root of X and the value of Q is also necessary

X = 1 minus root sign 2 into equation 2x ^ 2-4x + 3Q = 0
The result is: q = radical 2-2 / 3
The sum of two is equal to - B / 2A = 1
The other root is: 1 - (1 minus root 2) = root 2

It is known that one root of the equation 2x2-4x + 3Q = 0 on X is 1- 2, find its other root and the value of Q

Let the other root of the equation be X,
According to the relationship between root and coefficient,
Get 1-
2+x=2，
The solution is x = 1+
The other root is 1+
2．
Three more
2q=（1-
2）（1+
2）=-1，
The solution is q = - 2
3．

First, it is simplified and then evaluated (the square of a-4a + the square of a-4-2-a / 1) divided by the square of a-2a, where a is the root of the equation x squared + 3x + 1 = 0

(A's Square - 4A + 4) parts (A's Square - 4) - (2-A) divided by (a square - 2A) 2 parts
=(A-2) (a + 2) + (1 / 2) of (A-2)] divided by 2 parts of a (A-2)
=(a + 3) a (A-2)
=2 / 2 (a 2 + 3a)
=- 1 in 2

4x²+5x=81 x(x+5)=0 (2x-x)(x-1)=0 x(x+5)=5x-10 (3x-2)(x+1)=x(2x-1)

X1 = (- 5 + root 1321) / 8 or (- 5-root 1321) / 8
X2 = 0 or - 5
X3 = 1 or 0
X4 = no solution
X5 = - 1 + root3 or - 1-root3

Given that a polynomial plus - 5x? - 4x-3 is equal to - x? + 3x, find this polynomial

(-x²+3x)-(-5x²-4x-3)
=-x²+3x+5x²+4x+3
=4x²+7x+3

Given that the polynomial x ^ 3-x ^ 2 + 2x + K can be factorized, please tell the value of K and factorize the polynomial Good is rewarded

It is known that the polynomial x ^ 3-x ^ 2 + 2x + K can be factorized
Then: k = - 2
Original formula = x? - x? + 2x-2
=x²(x-1)+2(x-1)
=(x-1)(x²+2)

If x-3 is a factor of the polynomial 2x2-5x + m, then M is equal to () A. 6 B. -6 C. 3 D. -3

Substituting x = 3 into the equation 2x2-5x + M = 0, we get 18-15 + M = 0, and the solution is: M = - 3
Therefore, D

The square - 2x-3 factorization factor of polynomial x is_____________

(x-3)(x+1)

If the square + BX + C of the polynomial 2x is factorized into 2 (x-3) (x + 1), then the value of B and C is?

2（x-3)(x+1)=2(x^2-2x-3)=2x^2-4x-6
So B = - 4, C = - 6

Try to explain: the value of polynomial (5x? - 7x? Y + 3x? Y) + 2x? - (- 7x? Y + 3x? Y + 7x?) It has nothing to do with the values of the letters X and y.

（5x³-7x³y+3x²y）+2x³-（-7x³y+3x²y+7x³）
=5x³-7x³y+3x²y+2x³+7x³y-3x²y-7x³
=0