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8 G of NaOH reacts exactly with a certain amount of dilute hydrochloric acid to form a saturated solution of NaCl, the solubility of which is known to be 36 kg at this temperature, to obtain the mass of hydrochloric acid
NaOH + HCl = NaCl + H2O
40 36.5 58.5 18
8G xyz
X =7.3g y =11.7g z =3.6g
The mass of water in the saturated solution that fully reacts and forms NaCl is
36:100=11.7: A
A =32.5 g
The mass fraction of hydrochloric acid is
7.3G/(32.5g-3.6g+7.3g)*100%=20.17%
At a certain temperature, evaporate 35 g of saturated potassium chloride solution to obtain 10 g of potassium chloride, and obtain: (1) Solubility of potassium chloride at this temperature. (2) Mass fraction of solute in the saturated solution.
(1) According to the meaning, if there is 10 g of potassium chloride in 35 g of potassium chloride saturated solution, then there is 25 g of water, i.e. a maximum of 10 g of potassium chloride is dissolved in 25 g of water, and the solubility of potassium chloride at this temperature can be set as x, then
10G
25G=x
100G
X =40g
(2) The mass fraction of solute in the saturated solution was 10 g
35G×100%=28.6%
(1) According to the meaning, if there is 10 g of potassium chloride in the saturated solution of 35 g of potassium chloride, then there is 25 g of water, i.e. a maximum of 10 g of potassium chloride is dissolved in 25 g of water, and the solubility of potassium chloride at this temperature can be set as x, then
10G
25G=x
100G
X =40g
(2) The mass fraction of solute in the saturated solution was 10 g
35G×100%=28.6%
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