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100 G of saturated potassium chloride solution is heated and evaporated to dryness to obtain 25.4 g of potassium chloride solubility of potassium chloride
Solubility is the mass of the substance dissolved when saturated in 100 g of solvent
100 G of saturated potassium chloride solution was heated and dried to give 25.4 g of potassium chloride crystal
The mass of solvent (water) is then 100-25.4=74.6 g
74.6 G of water dissolved 25.4 g of potassium chloride
The mass of soluble potassium chloride in 100 g of water is then 25.4/74.6*100=34 g
Solubility of potassium chloride is 34 g
The potassium chloride had a solubility of 30 g at 10 degrees centigrade, and a potassium chloride solution of 500 g and 20% was available, and if 10 g of potassium chloride crystals were precipitated at 10 degrees centigrade (degrees centigrade The answer is 100Sorry. The potassium chloride had a solubility of 30 g at 10 degrees centigrade, and a potassium chloride solution of 500 g and 20% was available, and if it was allowed to precipitate 10 g of potassium chloride crystals at 10 degrees centigrade (excluding water of crystallization, what g of water to be evaporated The answer is 100Sorry.
500G 20% potassium chloride solution contains KCL mass=500*0.2=100g, so the mass of water m (H2O)=400g. It is known from the solubility that only when 120g KCL is dissolved can it be saturated. If 100g KCL is saturated, the corresponding water=(100*100)\30=1000\3. Therefore, evaporation (400-1000\3) g-1000\3) g of water. Next, it is evaporation.
RELATED INFORMATIONS
- 1. Solubility curve of potassium chloride can be found at 25°C 128? No, I thought it was 20,30 degrees,34,37
- 2. At 80°C, the solubility of potassium chloride was 51 grams. At this temperature, the potassium chloride solution was 240 grams. To form a saturated solution,51 grams of potassium chloride needed to be added. Senior, please help! At 80°C, the solubility of potassium chloride is 51 g. At this temperature, the potassium chloride solution is 240 g. To make a saturated solution,51 g of potassium chloride shall be added. How much g of potassium chloride is contained in the original solution? Senior, please help! At 80°C, the solubility of potassium chloride is 51 g. At this temperature, the potassium chloride solution is 240 g. To make a saturated solution,51 g of potassium chloride should be added. Senior, please help!
- 3. At 10°C, the solubility of potassium chloride is 31 g/100 g of water. The existing solution at 10°C is 393 g, in which 83 g of potassium chloride has been dissolved. How many grams of potassium chloride need to be added to form a saturated solution At 10°C, the solubility of potassium chloride is 31 g/100 g of water. The existing solution at 10°C is 393 g, in which 83 g of potassium chloride has been dissolved. How many g of potassium chloride need to be added to form a saturated solution
- 4. The solubility of sodium chloride is 36 g at 20°C, at which the mass fraction of solute in the sodium chloride solution is unlikely to be () A.20% B.26.5% C.25% D.30%
- 5. At 20°C,100g of 10% salt solution was treated as follows to obtain the mass fraction of solute in the solution At 20°C,100 g of 10% salt solution was treated as follows: Calculate the mass fraction of the solute in the resulting solution (assuming that each No solute precipitation or residue). (1) What is the mass fraction of the solute after evaporation of 10 g of water? (2) What is the mass fraction of solute after adding 10g NaCl? (3) What is the mass fraction of solute after adding 10g NaCl and 10g water? (4) What is the mass fraction of the solute after adding 100g of 15% NaCl? (5) What is the mass fraction of the solute after adding 20 g of water? (Please write out the calculation process)
- 6. Given a solubility of 36 g of sodium chloride at 20.d egree. C., the mass of sodium chloride in a saturated solution of 100 g of sodium chloride is ___ g The mass of water is __g. When the sodium chloride solid is 18g at 20°C,_g water shall be added to prepare the saturated solution.
- 7. At 20°C, the solubility of salt is known to be 36g. Now,50g salt is added to 50g water and fully dissolved, what is the mass fraction of solute in the solution?
- 8. The solubility of sodium chloride at 20.d egree. C. is known to be 36 g/100 g of water, and the mass value of sodium chloride in saturated sodium chloride solution at 20.d egree. C. is A 200 times 36 divided by 100 B 200 times 36 divided by 100 plus 36 C 200 times 100 divided by 36 D 200 by 36 divided by 100 minus 36
- 9. Sodium chloride has a solubility of 36 g at 20°C, at which the mass fraction of solute in the sodium chloride solution can not be 20%26.4%25%30% Sodium chloride has a solubility of 36 grams at 20 degrees Celsius, at which the mass fraction of solute in the sodium chloride solution is unlikely to be 20%26.4%25%30%
- 10. At 20°C, the salt solution with a solute content of 5%(mass fraction) of 100 g is treated as follows, and the solution in which the solute content increases every time is fully dissolved 1) After evaporating 10g of water, the mass fraction of solute is? 2) After adding 10g NaCl, the mass fraction of solute is? At 20°C, the salt solution with 100g solute content of 5% is treated as follows, and the solution with increasing solute content in the solution is completely dissolved 1) After evaporating 10g of water, the mass fraction of solute is? 2) After adding 10g NaCl, the mass fraction of solute is?
- 11. 53.6 G of a saturated solution of potassium chloride at 20.d egree. C. was evaporated to dryness to give 13.6 g of a crystal of potassium chloride for solubility Urgent! Urgent! 53.6 G of a saturated solution of potassium chloride at 20.d egree. C. was evaporated to dryness to give 13.6 g of a crystal of potassium chloride and to obtain its solubility Urgent! Urgent!
- 12. 8 G of NaOH reacts exactly with a certain amount of dilute hydrochloric acid to form a saturated solution of NaCl, the solubility of which is known to be 36 kg at this temperature, to obtain the mass of hydrochloric acid
- 13. Will the solubility of KCL change in NaCl solution? Would the solubility of KCL change in NaCl solution?
- 14. When ag water is evaporated from a salt solution at constant temperature, bg crystal without crystal water precipitates, and cg crystal without crystal water precipitates after ag water is evaporated, the mass fraction of solute in the original solution is () A.100(b+c) 2A+b+c% B.b+c 2A+b+c% C.100c A + c% D. Unable to determine When ag water is evaporated from a salt solution at constant temperature, bg crystal without crystal water precipitates, and cg crystal without crystal water precipitates after ag water is evaporated, the mass fraction of solute in the original solution is () A.100(b+c) 2A+b+c% B.b+c 2A+b+c% C.100c A + c% D. Not sure
- 15. Calculation of Chemical Solubility At 20°C, the solubility of copper sulfate is 21g. Now, when the anhydrous copper sulfate powder and the water are mixed at 20°C, the mixture is fully stirred and allowed to stand for a period of time. What is the ratio of the mass of the precipitated crystal to the mass of the original powder? The clearer the explanation the better, the clearer the explanation,
- 16. Solubility Calculation If there is 220g A material solution at t°C, add 10g water and then dissolve 10g A, the solution can be saturated; if there is 10g water and then dissolve 5g A, it is saturated. What is the solubility of A at t°C?
- 17. The solubility of KNO3 is 247 g/100 g of water at 100°C and 31 g/100 g of water at 20°C. If the saturated KNO3 solution at 86.75 g/100°C is evaporated and 15 g of water is cooled to 20°C, the mass of precipitated solid is? A.58.7g B.37.1g C.54.0g D.46.5g Help me see what went wrong: Let the mass of solute in the original solution be x X/86.75=247/247+100 X =61.75 Set the mass of solute after evaporating water and cooling as y Y/86.75-15=31/100+31 Y =17 Therefore, the precipitated crystal quality is 61.75-17=44.8
- 18. How does sodium chloride become sodium hydroxide
- 19. Is the solubility of NaCl increased or decreased when NaOH is added to NaCl?
- 20. 34 56 3 1 6 Equals?