53.6 G of a saturated solution of potassium chloride at 20.d egree. C. was evaporated to dryness to give 13.6 g of a crystal of potassium chloride for solubility Urgent! Urgent! 53.6 G of a saturated solution of potassium chloride at 20.d egree. C. was evaporated to dryness to give 13.6 g of a crystal of potassium chloride and to obtain its solubility Urgent! Urgent!

53.6 G of a saturated solution of potassium chloride at 20.d egree. C. was evaporated to dryness to give 13.6 g of a crystal of potassium chloride for solubility Urgent! Urgent! 53.6 G of a saturated solution of potassium chloride at 20.d egree. C. was evaporated to dryness to give 13.6 g of a crystal of potassium chloride and to obtain its solubility Urgent! Urgent!

13.6/(53.6-13.6)= X/100
X is solubility, that's all I' ve told you,20 years ago.

At a certain temperature, evaporate 35 g of saturated potassium chloride solution at a certain temperature to obtain 10 g of potassium chloride solubility of solute at this temperature At a certain temperature, evaporate 35 g of saturated potassium chloride solution to obtain 10 g of potassium chloride, and obtain the solubility of solute at this temperature

Mass of water in 35 g of solution 35-10=25 g
Solubility is the soluble mass in 100 g of water
S/100=10/25 S=40
Answer 40