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At 10°C, the solubility of potassium chloride is 31 g/100 g of water. The existing solution at 10°C is 393 g, in which 83 g of potassium chloride has been dissolved. How many grams of potassium chloride need to be added to form a saturated solution At 10°C, the solubility of potassium chloride is 31 g/100 g of water. The existing solution at 10°C is 393 g, in which 83 g of potassium chloride has been dissolved. How many g of potassium chloride need to be added to form a saturated solution
Suppose the mass of potassium chloride to be added is x (g)
M solute/m solvent = s/100
(83+X)/(393-83)=31/100
Solution x =13.1 g
Answer "13.1 g of potassium chloride is also required to prepare a saturated solution
Assume that the mass of potassium chloride added is x (g)
M solute/m solvent = s/100
(83+X)/(393-83)=31/100
Solution x =13.1 g
Answer "13.1 g of potassium chloride is also required to prepare a saturated solution
At 20°C,40 g of potassium chloride was added to 100 g of water and stirred sufficiently to form 134 g of potassium chloride solution.
The mass of the known solution is 134 g and the mass of the solvent is 100 g;
The mass of dissolved potassium nitrate is:134g-100g=34g;
Then mass fraction of the solute = mass of the solute
Mass of solution ×100%=34g
134G×100%=25.4%;
Set the solubility of potassium chloride at 20°C as S;
Then S
S+100g×100%25.4%;
Solution: S=34g.
Therefore, the answer is:25.4%;34.
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