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100 G of the solution of the substance A at 50 degrees centigrade was divided into two parts, one part evaporated at constant temperature 10 g of water with 4 g of crystals precipitated, the other part evaporated 20 g of crystals precipitated 20 g, Solubility in 50 degrees Celsius. Must have a process, thank you very much!
Make the assumption that the other portion evaporates 20 g and precipitates 20 g on the previous portion.
4G crystal precipitates from 10g water evaporated at a constant temperature, which must be a saturated solution.10g water evaporated on this basis is equivalent to 20g water evaporated from the original solution. The crystals precipitated in the latter stage are:20-4=16, indicating that 16g crystal is dissolved in 10g water, so the solubility at this temperature is 160g.
At 50 degrees centigrade,100 g of the solution of substance A was evaporated to 10 g of water at a constant temperature, and 4 g of crystal A was precipitated. If 20 g of water is evaporated from the original solution at a constant temperature,9 g of A crystal will precipitate, and the solubility of the substance at 50°C is?
Assume that the solubility of substance A at 50°C is S
(20G-10g)/(9g-4g)=100g/S
S=50g
So at 50 degrees Celsius A the solubility of the substance is 50 grams.
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