During the following chemical changes: XHCl YNaOH The substance represented by Z, X may be () A. Cu B. AgNO3 C. Ba (OH)2 D. CuO

During the following chemical changes: XHCl YNaOH The substance represented by Z, X may be () A. Cu B. AgNO3 C. Ba (OH)2 D. CuO

When A and X are copper, copper does not react with hydrochloric acid, so the selection is incorrect. When B and X are silver nitrate, silver nitrate reacts with hydrochloric acid to form silver chloride white precipitate and nitric acid. When nitric acid reacts with sodium hydroxide to form sodium nitrate and water, the selection is correct. When C and X are Ba (OH)2, Ba (OH)2 and hydrochloric acid...

When A and X are copper, copper does not react with hydrochloric acid, so the selection is incorrect. When B and X are silver nitrate, silver nitrate reacts with hydrochloric acid to form silver chloride white precipitate and nitric acid, and nitric acid reacts with sodium hydroxide to form sodium nitrate and water, so the selection is correct. When C and X are Ba (OH)2, Ba (OH)2 and hydrochloric acid...

Hydrochloric acid is added to the NaOH,Na2CO3, mixture if the amount of NaOH,Na2CO3,HCl substance is x, y, z, respectively (1) Calculate the amount of NaCl substance in the solution after the reaction (A) (2) It is known that Na2CO3 reacts with HCl according to the following formula: Na2CO3+HCl=NaHCO3+NaCL NaHCO3+HCl=NaCl+CO2↑+H2O Calculate the amount of carbonate ions in the solution after the reaction (B)

Anyway, if you look at the equation NaOH+HCl=NaCl+H2ONa2CO3+HCl=NaHCO3+HCl=NaCl+CO2↑+H2O, the return path of the last Cl is 1 or combined with H+, and HCl2 and Na+ pair to form NaCl, so 1 when HCl is excessive and appropriate, i.e. z≥x+2y, then the amount of NaCl' is from the angle of Na+...