Given that the absolute values of four rational numbers, a, b, c and d are 1,2,3 and 4 respectively, can we write a formula such that a+b+c+d=-1? Hope to give the answer now, if not, then tomorrow ~ Given that the absolute values of four rational numbers, a, b, c and d are 1,2,3 and 4, can we write a formula such that a+b+c+d=-1? Hope to give the answer now, if not, then tomorrow ~

Given that the absolute values of four rational numbers, a, b, c and d are 1,2,3 and 4 respectively, can we write a formula such that a+b+c+d=-1? Hope to give the answer now, if not, then tomorrow ~ Given that the absolute values of four rational numbers, a, b, c and d are 1,2,3 and 4, can we write a formula such that a+b+c+d=-1? Hope to give the answer now, if not, then tomorrow ~

It is not possible that the absolute value of a number is an odd number (1,3). The absolute value of the obtained number must be an even number, that is to say, the sum of three numbers whose absolute values are even can not be an odd number.
So it's a question with no answer.

It is not possible that the absolute value of the obtained number must be even, that is to say, the sum of three numbers whose absolute values are even can not be odd.
So it's a question with no answer.

It is known that a and b are mutually opposite numbers, c is the largest negative integer, the absolute value of x is 1, and d is the rational number with the smallest absolute value.

A + b =0,
C=-1,
X =1 or -1,
D =0
(A+b)/3058+x-c+d
0+X-(-1)+0
=1+X
=2 Or 0