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When X=-2, the value of the algebraic equation AX to the fifth power + BX to the third power + CX-5 to the seventh power, the value of the algebraic equation X=2? When X=-2, the value of the algebraic equation AX to the fifth power + the value of the third power of BX + the value of CX-5 to the third power is 7, find the value of this algebraic equation when X=2. When X=-2, the value of the algebraic formula AX to the fifth power + the value of the third power of BX + the value of CX-5 to the third power of CX is 7, find the value of this algebraic formula when X=2.
Substitute X=-2 into AX^5+BX3+CX-5=7 to obtain: A×(-2)^5+B×(-2)3+C×(-2)-5=7-32A-8B-2C=1232A+8B+2C=-12 when X=2AX^5+BX3+CX-5=A×2^5+B×23+C×2-5=32A+8B+2C-5=-12-5=-17
Given that A is the rational number with the smallest absolute value, the opposite number of b is 2,|c|=5, and b, c are different, find the value of a-b-c. -2/3/2/3/1[(-2/5/4)-(-0.2)-1/5] Ask for answers! High marks! ~~
From the question: a:0
B:-2
C:5
A-b-c=0-(-2)-5=-3
I'm sorry. I do n' t understand what's down there.
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