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Given that the 8th power of x - the 4th power of x +1=0, find the value of the 2008th power of x - the 2004th power of x + the 2000th power of x Given that the 8th power of x - the 4th power of x +1=0, find the value of the 2008 power of x - the 2004 power of x + the 2000 power of x
X^8-x^4+1=0
X^2008- x^2004+ x^2000
= X^2000(x^8-x^4+1)
=0
If x squared plus x equals 1, then the cube of 2002x plus the square of 2001x minus 2003x minus 2004
X^2=1-x
2001X^2=2001(1-x)
X^3=x-x^2=2x-1
2002X^3+2001x^2-2003x-2004=-2005
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